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- A particle moving downward at a speed of 6.0106 m/s enters a uniform magnetic field that is horizontal and directed from east to west. (a) If the particle is deflected initially to the north in a circular arc, is its charge positive or negative? (b) If B = 0.25 T and the charge-to-mass ratio (q/m) of the particle is 40107 C/kg. what is ±e radius at the path? (c) What is the speed of the particle after c has moved in the field for 1.0105s ? for 2.0s?At a particular instant an electron is traveling west to east with a kinetic energy of 10 keV. Earth's magnetic field has a horizontal component of 1.8105 T north and a vertical component of 5.0105 T down. (a) What is the path of the election? (b) What is the radius of curvature of the path?In Niels Bohr’s 1913 model of the hydrogen atom, the single electron is in a circular orbit of radius 5.29 × 10−11 m and its speed is 2.19 × 106 m/s. (a) What is the magnitude of the magnetic moment due to the electron’s motion? (b) If the electron moves in a horizontal circle, counterclockwise as seen from above, what is the direction of this magnetic moment vector?
- An electron in a TV CRT moves with a speed of 6.0107 m/s, in a direction perpendicular to Earth's field, which has a strength of 5.0105 T. (a) What strength electric field must be applied perpendicular to the Earth’s field to make the election moves in a straight line? (b) If this is done between plates separated by 1.00 cm, what is the voltage applied? (Note that TVs are usually surrounded by a ferromagnetic material to shield against external magnetic fields and avoid the need for such a collection,)(a) What is the force per meter on a lightning bolt at the equator that carries 20,000 A perpendicular to Earth’s 3.0105field? (b) What is the direction of the force if the current is straight up and Earth’s field direction is due north, parallel to the ground?Part D A particle with charge – 5.10 nC is moving in a uniform magnetic field B = -( 1.30 T )k. The magnetic force on the particle is measured to be F = -( 3.10x10-7 N )î+( 7.60×10-7 N )3. Calculate the scalar product i · F. Assume the velocity has only components found in the previous parts. Express your answer in meters per second times newtons. ν ΑΣφ v. F = m/s · N Submit Request Answer Part E What is the angle between i and F? Give your answer in degrees. Express your answer in degrees. Hνα ΑΣφ ?
- E A charge of 1.1 C having an initial velocity of 3.91+4.1k m/s enters a region with an electric field E=3.4k N/C and a magnetic field B=4.27+3.9k T. Calculate the magnitude of the force on the charge immediately after it enters the region. Express your answer in Newtons (write just the value, not the unit), rounding to one digit after the decimal separator. Yanitinizi ekleyin.E A charge of 1.2 C having an initial velocity of=3.91 3.3k m/s enters a region with an electric field E=3.11 N/C and a magnetic field B=3.71+4.2k T. Calculate the magnitude of the force on the charge immediately after it enters the region. Express your answer in Newtons (write just the value, not the unit), rounding to one cigit after the decimal separator. Add your answerPart D A particle with charge – 5.10 nC is moving in a uniform magnetic field B= -(1.26 T )k. The magnetic force on the particle is measured to be Calculate the scalar product v· F. Assume the velocity has only components found in the previous parts. F = -( 3.10x10-7 N )ê+(7.60x10-7 N )3. Express your answer in meters per second times newtons. Nνα ΑΣφ ? m/s N Submit Request Answer Part E What is the angle between v and F? Give your answer in degrees. Express your answer in degrees. ? = Submit Request Answer Provide Feedback
- Part B A particle with charge – 5.10 nC is moving in a uniform magnetic field B= -(1.26 T )k. The magnetic force on the particle is measured to be F = -( 3.10x10-7 N)i+(7.60x10-7 N )3. Calculate the x-component of the velocity of the particle. Express your answer in meters per second. Hν ΑΣφ Vx = m/s Submit Request Answer Part C Calculate the y-component of the velocity of the particle. Express your answer in meters per second. ? Vy = m/sAsapA current of 5.72 A flows along a wire with = (1.382 - 2.095 ) m. The wire resides in a uniform magnetic field B = (-0.350 +0.700 ) T. What is the magnetic force acting on the wire? (Express your answer in vector form.) N