Part A Proton-beam therapy can be preferable to X rays for cancer treatment (although much more expensive) because protons deliver most of their energy to the tumor, with less damage to healthy tissue. A cyclotron used to accelerate protons for cancer treatment repeatedly passes the protons through a 15-kV potential difference. How many passes are needed to bring the protons' kinetic energy to 1.5 x 10–11 J? Hνα ΑΣφ ? N = 3125 Submit Previous Answers Request Answer X Incorrect; Try Again

Part A Proton-beam therapy can be preferable to X rays for cancer treatment (although much more expensive) because protons deliver most of their energy to the tumor, with less damage to healthy tissue. A cyclotron used to accelerate protons for cancer treatment repeatedly passes the protons through a 15-kV potential difference. How many passes are needed to bring the protons' kinetic energy to 1.5 x 10–11 J? Hνα ΑΣφ ? N = 3125 Submit Previous Answers Request Answer X Incorrect; Try Again

Physics for Scientists and Engineers with Modern Physics

10th Edition

ISBN:9781337553292

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter43: Nuclear Physics

Section: Chapter Questions

Problem 3P

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The magnetic field in a cyclotron is 1.25 T, and the maximum orbital radius of the circulating protons is 0.40 m. (a) What is the kinetic energy of the protons when they are ejected from the cyclotron? (b) What Is this energy in MeV? (c) Through what potential difference would a proton have to be accelerated to acquire this kinetic energy? (d) What is the period of tire voltage source used to accelerate the piotons? (e) Repeat tire calculations for alpha-particles.
The power output of the Sun is 41026 W. (a) If 90% of this energy is supplied by the proton-proton chain, how many protons are consumed per second? (b) How many neutrinos per second should there be per square meter at the surface of Earth from this process?
(a) Calculate the mass of a proton using the charge-to-mass ratio given for it in this chapter and its known charge. (b) How does your result compare with the proton mass given in this chapter?
H.W-A CRT has an effective deflection length of 2 Cm and distance of 1 mm. The acceleration voltage is 2 KV. If the electron mass and charge are 9.1 * 10-31 Kg and 1.6 * 10-19 C. Determine:- 1- The coordinate of the point at which the electron beam leaves the plates? 2- The maximum velocity. 3- The distance of which the screen be placed to produce deflection of 5 Cm on the screen.
You have been linked to a version of you where you have hotdogs for fingers, fearing that Jotaro is coming for your life you need to get back, and in order to get back you need to supply a specific amount of electricity to your pinky toe with a battery from a princess playhouse. However the conversions are different here, supplied with the knowledge from Alphaverse Waymond figure out how much energy is needed to supply 5 eV to your pinky toe. How much haays is needed? (1eV=1.6x10^-19 J; 1 J = 5 aken; 1 aken = 30 haays) a. 1.2 x 10^-16 haays b. 1.125 x 10 ^ 22 haays c. 4.5 x 10 ^ 20 haays d. 5.0 x 10 ^ 17 haays
The poles of a 150V battery are connected to two parallel plates with an area of 30 cm² and a distance of 10. between them, as shown in the figure. A beam of alpha particles (9.+2lqal, Igal=1.6x10 ª C and m-6.64x107| kej starts from rest, accelerates with a potential difference of 10 kV and enters the interplate region with an electric field perpendicular to the direction of motion. What is the magnitude and direction of the magnetic field needed for alpha particles to emerge from between the plates without deviating? I5O V (e B-0.0612 T outLward from the plane of the page B-0.0306 Toutward from the plane of the page B=0 0153Tinward from the plane of the page B=0,0153 Toutward from the plane of the page B=0,0306 T oward from the plar: of the pege Leave blank 描
An alpha particle is whizzing by at a velocity determined by its KE of 5 Mev. a ) What is the velocity of the alpha particle? b) What is the magnetic field at the position of a nucleus 2nm away from the alpha particle at angle of 900 to the velocity of the alpha. Alpha particle has charge of 2e but mass of 4 protons.
What value of B should be used in a velocity selector to separate out 2.0-keV protons if E is fixed at 80 kV/m?
A proton experiences a 5,000V decrease in electric potential. Assuming the proton started from rest: a. Express its energy in Mev b. After being accelerated, the proton enters a 5.0 Tesla magnetic field perpendicular to its velocity. Calculate the radius of the circle the proton will travel.
80 If the acceleration potential (peak voltage, 50,000) has a frequency of 1.2 x 107 c/s, find the field strength for cyclotron resonance when deuterons and alpha particles, respectively are accelerated. For how long are the parti- cles accelerated if the radius of orbit at ejection is 30.0 cm? Deuteron rest mass = 2.01 amu. a-particle rest mass = 4.00 amu [University of New Castle 1965]
A simple mass spectrometer may include an electron ionization (EI) source and magnetic sector mass analyzer. In this type of instrument, singly charged ions are produced and accelerated through the slit to the analyzer by applying high potentials to accelerator plates. If an ion with mass 339 amu and charge z = 1 is accelerated by a potential of 6500 V, what is its kinetic energy (in J)? Note: The following information may be useful for solving the two parts of this problem. 1 amu = 1.66 x 10-27 kg Electronic charge, e = 1.602 x 10-19 C 1J = 1 kg m/s² 1 V = 1 J/C Submit Answer What is the velocity of the ion?
The accleration of protons in a cyclotron is shown in the figure below. The magnetic field in a cyclotron is 1.25 T, and the maximum orbital radius of the circulating protons is 0.4 m. The mass of a proton is 1.67-10-27 kg and the charge on a proton is 1.6-10-1⁹9 C. Dee O b. What is this energy in MeV? KE at ejection in MeV = O OIOIO 1 1 O 1 10 O Ion source O O O O Electric oscillator MeV MV O O 1 Electric field region where kinetic energy is gained Deflector plate Target a. What is the kinetic energy of the protons when they are ejected from the cyclotron? KE at ejection = S Proton beam c. Through what total potential difference (potential difference between the gaps and number of trips through the gaps) would a proton have to be accelerated to acquire this kinetic energy? Think about the magnitude of potential you have calculated. While designing the cyclotron, gap potential can be made much smaller than this magnitude by making the proton pass through the gap several times by making…