Part A A stockroom worker pushes a box with mass 14.0 kg on a horizontal surface with a constant speed of 3.10 m/s. The coefficients of kinetic and static friction between the box and the surface are 0.290 and 0.500, respectively. You may want to review (Page). For general problem-solving tips and strategies for this topic, you may want to view a Video Tutor Solution of Delivering the goods. What horizontal force must the worker apply to maintain the motion of the box? Assume + direction coincides with the direction of velocity. ▸ View Available Hint(s) Fx = 39.8 N Submit Previous Answers Part B Correct If the worker stops pushing, what will be the acceleration of the box? Assume + direction coincides with the direction of velocity. View Available Hint(s) Hint 1. How to approach the problem In Part A, you would have found an expression for the motion of the box in the horizontal direction using Newton's second law. In that expression, let the force applied by the worker equal zero and assume the box is accelerating. You shou then be able to obtain an expression for the acceleration of the box. Be sure to consider the direction of the forces. ΜΕ ΑΣΦ a = 2.84 Submit Previous Answers Request Answer × Incorrect; Try Again ? m/s²
Part A A stockroom worker pushes a box with mass 14.0 kg on a horizontal surface with a constant speed of 3.10 m/s. The coefficients of kinetic and static friction between the box and the surface are 0.290 and 0.500, respectively. You may want to review (Page). For general problem-solving tips and strategies for this topic, you may want to view a Video Tutor Solution of Delivering the goods. What horizontal force must the worker apply to maintain the motion of the box? Assume + direction coincides with the direction of velocity. ▸ View Available Hint(s) Fx = 39.8 N Submit Previous Answers Part B Correct If the worker stops pushing, what will be the acceleration of the box? Assume + direction coincides with the direction of velocity. View Available Hint(s) Hint 1. How to approach the problem In Part A, you would have found an expression for the motion of the box in the horizontal direction using Newton's second law. In that expression, let the force applied by the worker equal zero and assume the box is accelerating. You shou then be able to obtain an expression for the acceleration of the box. Be sure to consider the direction of the forces. ΜΕ ΑΣΦ a = 2.84 Submit Previous Answers Request Answer × Incorrect; Try Again ? m/s²
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
Transcribed Image Text:Part A
A stockroom worker pushes a box with mass 14.0
kg on a horizontal surface with a constant speed of
3.10 m/s. The coefficients of kinetic and static
friction between the box and the surface are 0.290
and 0.500, respectively.
You may want to review (Page).
For general problem-solving tips and strategies for
this topic, you may want to view a Video Tutor
Solution of Delivering the goods.
What horizontal force must the worker apply to maintain the motion of the box?
Assume + direction coincides with the direction of velocity.
▸ View Available Hint(s)
Fx = 39.8 N
Submit
Previous Answers
Part B
Correct
If the worker stops pushing, what will be the acceleration of the box?
Assume + direction coincides with the direction of velocity.
View Available Hint(s)
Hint 1. How to approach the problem
In Part A, you would have found an expression for the motion of the box in the
horizontal direction using Newton's second law. In that expression, let the force
applied by the worker equal zero and assume the box is accelerating. You shou
then be able to obtain an expression for the acceleration of the box. Be sure to
consider the direction of the forces.
ΜΕ ΑΣΦ
a = 2.84
Submit Previous Answers Request Answer
× Incorrect; Try Again
?
m/s²
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