One end of a cord is fixed and a small 0.250-kg object is attached to the other end, where it swings in a section of a vertical circle of radius 1.50 m, as shown in the figure below. When 0 = 26.0°, the speed of the object is 7.50 m/s. 18 (a) At this instant, find the magnitude of the tension in the string. (b) At this instant, find the tangential and radial components of acceleration. m/s? downward tangent to the circle m/s2 inward a. = (c) At this instant, find the total acceleration. inward and below the cord at (d) Is your answer changed if the object is swinging down toward its lowest point instead of swinging up? O Yes O No

An Introduction to Physical Science
14th Edition
ISBN:9781305079137
Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Publisher:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Chapter2: Motion
Section2.3: Acceleration
Problem 2.3CE: What is the average speed in mi/h of a person at the equator as a result of the Earths rotation?...
icon
Related questions
Question
100%
One end of a cord is fixed and a small 0.250-kg object is attached to the other end, where it swings in a section of a vertical circle of radius 1.50 m, as shown in
the figure below. When 0 = 26.0°, the speed of the object is 7.50 m/s.
(a) At this instant, find the magnitude of the tension in the string.
(b) At this instant, find the tangential and radial components of acceleration.
m/s2 downward tangent to the circle
a =
m/s- inward
(c) At this instant, find the total acceleration.
inward and below the cord at
(d) Is your answer changed if the object is swinging down toward its lowest point instead of swinging up?
O Yes
O No
Transcribed Image Text:One end of a cord is fixed and a small 0.250-kg object is attached to the other end, where it swings in a section of a vertical circle of radius 1.50 m, as shown in the figure below. When 0 = 26.0°, the speed of the object is 7.50 m/s. (a) At this instant, find the magnitude of the tension in the string. (b) At this instant, find the tangential and radial components of acceleration. m/s2 downward tangent to the circle a = m/s- inward (c) At this instant, find the total acceleration. inward and below the cord at (d) Is your answer changed if the object is swinging down toward its lowest point instead of swinging up? O Yes O No
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 3 images

Blurred answer
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
An Introduction to Physical Science
An Introduction to Physical Science
Physics
ISBN:
9781305079137
Author:
James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Publisher:
Cengage Learning