Nuclear Fusion Reaction In a human-scale model of a nuclear fusion reaction, two "deuterons" smash together head-on. Each has a mass of 2.0147kg and is moving at speed va- The result is a "Helium-3 nucleus" (mass 3.0160kg) and a separate "neutron" (mass 1.0090kg). Amazingly, this reaction produces a positive Wne of 3.96 × 1014 J -- by converting mass into kinetic energy as predicted by Einstein's E = mc². The "neutron" moves with a speed of v₂ after the reaction. E + + D D ³He N. Proton Neutron http://fusion.srubar.net 4 Vd 1.57×107 m (no answer) Correct Answer: 3.64 Un x10m S

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Nuclear Fusion Reaction
In a human-scale model of a nuclear fusion reaction, two
"deuterons" smash together head-on. Each has a mass of
2.0147kg and is moving at speed vd.
The result is a "Helium-3 nucleus" (mass 3.0160kg) and a separate
"neutron" (mass 1.0090kg). Amazingly, this reaction produces a
positive Wnc of 3.96 × 10 14 J -- by converting mass into kinetic
energy as predicted by Einstein's E mc²
=
The "neutron" moves with a speed of un after the reaction.
E
4
☑
Vd
1.57×107 m
(no answer)
Correct Answer: 3.64
S
Un
×107 m
S
+
+
D D
3Не
N.
Proton
Neutron
http://fusion.srubar.net
Transcribed Image Text:Nuclear Fusion Reaction In a human-scale model of a nuclear fusion reaction, two "deuterons" smash together head-on. Each has a mass of 2.0147kg and is moving at speed vd. The result is a "Helium-3 nucleus" (mass 3.0160kg) and a separate "neutron" (mass 1.0090kg). Amazingly, this reaction produces a positive Wnc of 3.96 × 10 14 J -- by converting mass into kinetic energy as predicted by Einstein's E mc² = The "neutron" moves with a speed of un after the reaction. E 4 ☑ Vd 1.57×107 m (no answer) Correct Answer: 3.64 S Un ×107 m S + + D D 3Не N. Proton Neutron http://fusion.srubar.net
Solution:
Conservation of momentum:
mava + ma(-va) = Mn Vn + MH (-VH)
Solve for VH:
VH
=
Mn
ΜΗ
Un (Eqn. 1)
Conservation of energy (with positive Wnc):
2 (mav²) + Wne = ½ m² v²/₁₂ + ½ mн V²/
пс
Plug in for VH from (Eqn. 1):
2 (mav²) + Wnc = m₁v² + ½ m
Clean up:
пс
mav²/2 + Wnc = 1 / (mn +
m²
ΜΗ
ບ
Plug in masses of "particles" and Wnc:
Mn Un
ΜΗ
2)²
(2.0147kg) + (3.96 × 10 14 J) = (.6733kg)v
Transcribed Image Text:Solution: Conservation of momentum: mava + ma(-va) = Mn Vn + MH (-VH) Solve for VH: VH = Mn ΜΗ Un (Eqn. 1) Conservation of energy (with positive Wnc): 2 (mav²) + Wne = ½ m² v²/₁₂ + ½ mн V²/ пс Plug in for VH from (Eqn. 1): 2 (mav²) + Wnc = m₁v² + ½ m Clean up: пс mav²/2 + Wnc = 1 / (mn + m² ΜΗ ບ Plug in masses of "particles" and Wnc: Mn Un ΜΗ 2)² (2.0147kg) + (3.96 × 10 14 J) = (.6733kg)v
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