Platformv0 =0Vo= 4.39 m/s9.49 m/sVO4.24 m/sVo(e) vo = 12.61 m/shiOdbOhpNow the system is adjusted so the spring launcher sits aims upward at an angle = 30° from horizontal.The sphere is launched from the same height h = 1.7 m above the floor. The bucket is moved to a newlocation, db,new = 2.5 m from the end of the platform and is h = 1.02 m above the floor as shown in thefigure.bucketWhat must be the launch velocity vo of the ball bearings from the launcher so that they land in the bucket?= 4.94 m/sBox

Name: Platformv0 =0Vo= 4.39 m/s9.49 m/sVO4.24 m/sVo(e) vo = 12.61 m/shiOdbO
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Description: Platformv0 =0Vo= 4.39 m/s9.49 m/sVO4.24 m/sVo(e) vo = 12.61 m/shiOdbOhpNow the system is adjusted so the spring launcher sits aims upward at an angle = 30° from horizontal.The sphere is launched from the same height h = 1.7 m above the floor. The bu

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Now the system is adjusted so the spring launcher sits aims upward at an angle = 30° from horizontal. The sphere is launched from the same height h = 1.7 m above the floor. The bucket is moved to a new 2.5 m from the end of the platform and is h = 1.02 m above the floor as shown in the location, db,new figure. - What must be the launch velocity vo of the ball bearings from the launcher so that they land in the bucket?

Now the system is adjusted so the spring launcher sits aims upward at an angle = 30° from horizontal. The sphere is launched from the same height h = 1.7 m above the floor. The bucket is moved to a new 2.5 m from the end of the platform and is h = 1.02 m above the floor as shown in the location, db,new figure. - What must be the launch velocity vo of the ball bearings from the launcher so that they land in the bucket?

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter4: Two-and-three Dimensional Motion

Section: Chapter Questions

Problem 10PQ

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