Normal, friction and drag are sometimes called "contact" forces because objects (fluids like air count here) must be in contact with each other in order for the force to operate. Cite an example of a force where objects do not need to be in contact with each other. Hint: You used one of them in this lab.

Normal, friction and drag are sometimes called "contact" forces because objects (fluids like air count here) must be in contact with each other in order for the force to operate. Cite an example of a force where objects do not need to be in contact with each other. Hint: You used one of them in this lab.

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Description: Normal, friction and drag are sometimes called "contact" forces because objects(fluids like air count here) must be in contact with each other in order for the force tooperate. Cite an example of a force where objects do not need to be in contact wi

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter6: Applications Of Newton’s Laws Of Motion

Section: Chapter Questions

Problem 1PQ: In many textbook problems, we ignore certain complications such as friction and drag. The problems...

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In many textbook problems, we ignore certain complications such as friction and drag. The problems contain key words that indicate such a simplification is being used. For example, if a surface is described as slippery, it means that we can ignore friction. Look at the previous chapters problem sets. Find five uses of these key words and explain how to interpret each case.
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Problem Find the particle's horizontal position x(1) and velocity v(x) at any point in a fluid whase drag force is expressed as Farag - kmy where, k is a constant, m is the mass of the particle and v is its velocity. Consider that the particle is initially traveling with a velocity vo. Solution: a) To salve for the position as a function of time x(1), we construct the net force in the x-axis as EF-F m Then: v- m since: a- dy/di Lhen by integrating, we obtain the following expression: Further, employing the rules of integration results to the following expression for position as a function of tLime x- (vo as t+ 0, the positian becomes x- vo/k b) To solve for the velocity as a function of position v(x), we construct the net force in the x-axis as follows F- - m Then: -mi y- m since: a- dy/dt Lhen -mi y- m We can eliminate time by expressing, the velacity on the left side of the equation as v- dx/dt Then, we arrive at the following expression By integrating and applying the limits, we…
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