m = 0.593 kg of methanol in atmospheric pressure is heated with an electric heater from T₁ = 30.2 °C to its boiling point. After the heating my methanol is vaporized. Heating and vaporizing takes t = 450.41 s with n=0.59 heater's efficiency. What is the volume of methanol? V = m³ Your last answer was interpreted as follows: 1 What is the energy required for heating? Eh = kJ Your last answer was interpreted as follows: 1 What is the energy required for vaporizing? E = Your last answer was interpreted as follows: 1 0.3 kg of the

icon
Related questions
Question
m = 0.593 kg of methanol in atmospheric pressure is heated with an electric heater from T₁ = 30.2 °C to its boiling point. After the heating my
methanol is vaporized. Heating and vaporizing takes t = 450.41 s with n=0.59 heater's efficiency.
What is the volume of methanol?
V =
What is the energy required for heating?
E₁ = 1
kJ
m³
Your last answer was interpreted as follows: 1
What is the energy required for vaporizing?
Ev = 1
kJ
Your last answer was interpreted as follows: 1
What is the power of the heater?
P = 1
с
Your last answer was interpreted as follows: 1
Your last answer was interpreted as follows: 1
What is the electr. energy needed for heating and vaporizing?
Eε = 1
kJ
Your last answer was interpreted as follows: 1
h
Do not leave any fields blank. If you don't know the answer, insert 1 for example.
Insert the answer with 3 significant digits
without rounding the answer.
Constant
P
Tb
Value Unit
2.53
1165
786.3
64.7 °C
umges
Quantity
heat capacity
kg K
kJ
kW
kg
kg
LAN
Symbol
h
heat of vaporization
power of the heater
efficiency of the heater
time of heating
energy required for heating
Eh
energy required for vaporizing
Ev
electr. energy needed for heating and vaporizing Ee
total mass of methanol
mass of vaporized methanol
volume of methanol
density of methanol
temperature
initial temperature
boiling point
P
t
√ > NEG
M
My
V
P
T
T₁
Unit
kJ
kg K
kJ
kg
kW
då du EEE
kJ
kg
kg
°C
°C
Input instruction
с
h
P
eta
t
E_h
E_v
E_e
m
m_v
V
rho
T
T_1
T_b
-
0.3 kg of the
Transcribed Image Text:m = 0.593 kg of methanol in atmospheric pressure is heated with an electric heater from T₁ = 30.2 °C to its boiling point. After the heating my methanol is vaporized. Heating and vaporizing takes t = 450.41 s with n=0.59 heater's efficiency. What is the volume of methanol? V = What is the energy required for heating? E₁ = 1 kJ m³ Your last answer was interpreted as follows: 1 What is the energy required for vaporizing? Ev = 1 kJ Your last answer was interpreted as follows: 1 What is the power of the heater? P = 1 с Your last answer was interpreted as follows: 1 Your last answer was interpreted as follows: 1 What is the electr. energy needed for heating and vaporizing? Eε = 1 kJ Your last answer was interpreted as follows: 1 h Do not leave any fields blank. If you don't know the answer, insert 1 for example. Insert the answer with 3 significant digits without rounding the answer. Constant P Tb Value Unit 2.53 1165 786.3 64.7 °C umges Quantity heat capacity kg K kJ kW kg kg LAN Symbol h heat of vaporization power of the heater efficiency of the heater time of heating energy required for heating Eh energy required for vaporizing Ev electr. energy needed for heating and vaporizing Ee total mass of methanol mass of vaporized methanol volume of methanol density of methanol temperature initial temperature boiling point P t √ > NEG M My V P T T₁ Unit kJ kg K kJ kg kW då du EEE kJ kg kg °C °C Input instruction с h P eta t E_h E_v E_e m m_v V rho T T_1 T_b - 0.3 kg of the
Expert Solution
steps

Step by step

Solved in 4 steps with 3 images

Blurred answer