Learning Goal: To be able to calculate the energy of a charged capacitor and to understand the concept of energy associated with an electric field. The energy of a charged capacitor is given by U = QV/2, where Q is the charge of the capacitor and V is the potential difference across the capacitor. The energy of a charged capacitor can be described as the energy associated with the electric field created inside the capacitor In this problem, you will derive two more formulas for the energy of a charged capacitor, you will then use a parallel-plate capacitor as a vehicle for obtaining the formula for the energy density associated with an electric field. It will be useful to recall the definition of capacitance, C = Q/V, and the formula for the capacitance of a parallel-plate capacitor, C = 60 A/d, where A is the area of each of the plates and d is the plate separation. As usual, is the permittivity of free space. First, consider a capacitor of capacitance C that has a charge Q and potential difference V. ▾ Part A Find the energy U of the capacitor in terms of C and Q by using the definition of capacitance and the formula for the energy in a capacitor. Express your answer in terms of C and Q. U= ΠΫΠΙ ΑΣΦ Submit Request Answer ?
Learning Goal: To be able to calculate the energy of a charged capacitor and to understand the concept of energy associated with an electric field. The energy of a charged capacitor is given by U = QV/2, where Q is the charge of the capacitor and V is the potential difference across the capacitor. The energy of a charged capacitor can be described as the energy associated with the electric field created inside the capacitor In this problem, you will derive two more formulas for the energy of a charged capacitor, you will then use a parallel-plate capacitor as a vehicle for obtaining the formula for the energy density associated with an electric field. It will be useful to recall the definition of capacitance, C = Q/V, and the formula for the capacitance of a parallel-plate capacitor, C = 60 A/d, where A is the area of each of the plates and d is the plate separation. As usual, is the permittivity of free space. First, consider a capacitor of capacitance C that has a charge Q and potential difference V. ▾ Part A Find the energy U of the capacitor in terms of C and Q by using the definition of capacitance and the formula for the energy in a capacitor. Express your answer in terms of C and Q. U= ΠΫΠΙ ΑΣΦ Submit Request Answer ?
Chapter8: Capacitance
Section: Chapter Questions
Problem 77CP: A spherical capacitor is formed from two concentric spherical conducting spheres separated by...
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Question
Transcribed Image Text:Item 7
Learning Goal:
To be able to calculate the energy of a charged capacitor and to understand
the concept of energy associated with an electric field.
The energy of a charged capacitor is given by U = QV/2, where Q is the
charge of the capacitor and V is the potential difference across the
capacitor. The energy of a charged capacitor can be described as the
energy associated with the electric field created inside the capacitor.
In this problem, you will derive two more formulas for the energy of a
charged capacitor; you will then use a parallel-plate capacitor as a vehicle
for obtaining the formula for the energy density associated with an electric
field. It will be useful to recall the definition of capacitance, C = Q/V, and
the formula for the capacitance of a parallel-plate capacitor,
C = €0 A/d, where A is the area of each of the plates and d is the plate
separation. As usual, eo is the permittivity of free space.
First, consider a capacitor of capacitance C that has a charge and potential difference V.
Part A
Find the energy U of the capacitor in terms of C and Q by using the definition of capacitance and the formula for the energy in a capacitor.
Express your answer in terms of C and Q.
ΠΑΣΦ
U =
Submit
Request Answer
?
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