In her chemistry class, Rachel is preparing a special solution for an experiment that she has to complete. The concentration of the solution can be modelled by the rule C = 1.44 log.(0.56t) Where C is the concentration in moles per litre (M) and t represents the time of mixing in seconds. Find the concentration of the solution after 15 seconds of mixing. O How long does it take, in minutes and seconds, for the concentration of the solution to reach 10 M? (use analytical method- by solving mathematical equation) Use Microsoft excel to plot the graph of C vs t (0.5 sts 15)
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- In the Analytical Chemistry laboratory, one of the B.Sc student Ms. Fatma wanted to analyze the presence of Iron(II) ion in the water samples collected from Sohar Industrial Area in the Sultanate of Oman and analyzed by Spectrophotometric method. (1) 250.00 mL of this water sample (Solution A) known to contain unknown amount of FeSO4. She has diluted Solution A by a dilution factor 10 to make 250.00 mL solution, which she labeled Solution B. Using Spectrophotometer, she has measured the absorbance value (0.642) for Solution B at 508 nm using 1.00 cm cell (cuvet). The molar absorptivity value for Fe2* ion at 508 nm is ɛ508 = 30.8 M-1cm1. (i) What volume of the solution A did she require to make the 250.00 mL of Solution В? (ii) in (i)? What instrument should she use to transfer the volume of the Solution A calculated (ii) Concentration of FeSO4 in Solution B. (iv) Concentration of FeSO4 in Solution A. Mass of FeSO4 in Solution A (Show your calculation) (v)OCHEMICAL REACTIONS Dilution A chemist must prepare 875. ml. of 335. M aqueous copper (11) fluoride (CuF) working solution. She'll do this by pouring out some 407. µμM aqueous copper (11) fluoride stock solution into a graduated cylinder and diluting it with distilled water. Calculate the volume in ml. of the copper (11) fluoride stock solution that the chemist should pour out. Round your answer to 3 significant digits. 0 04 0/5 YA teacher developed a new chemical - NONDISTRACTUS, which allows students to focus in the classroom more and not be distracted by random events. For NONDISTRACTUS to be effective there must be a minimum concentration in the student's body of 2.00 x10-3 mol / L. If the concentration falls below this level, the students are faced with a 10 min nonproductive period where they cannot focus on anything. NONDISTRACTUS was found to undergo a very rapid first-order decay with a half-life (t½) in the bodies of students of 23 min. Based on this information:a) What is the rate law constant, k?b) If the student starts off with an initial concentration of 2.25 x 10-2 mol / L dose, how long will it be until the concentration is above the minimum 2.00 x 10-3 mol / L? Will it ensure that they are not distracted for the entire test?
- 1. "Diffusion" sounds slow, but on the scale of a cell it is very fast. The average instantaneous velocity of a particle in solution is v= (kT/m)", where k = 1.38 X 101 g cm?/K sec², T= temperature in K, m = mass in g/molecule. A) Calculate the instantaneous velocity of a molecule of glucose and a molecule of myoglobin (a protein), at 37°C [molecular mass for glucose = 180 g/mol; molecular mass for myoglobin = 15,000 g/mol].Standardization of Sodium Hydroxide (NaOH) Solution Mass of KHP used (g) Initial buret reading (mL) Final Buret reading (mL) Link to video explaining how to do the following calculations Volume of base used (mL) Molarity of the NaOH solution (M) Titration of the Acetic Acid in Vinegar - WATCH THE VIDEO FOR A CALCULATION WALKTHRU Volume (mL) of Vinegar used Initial buret reading (mL) Final buret reading (mL) Volume of base used (mL) Molarity of the Acetic Acid in the Vinegar (M) HINT: Use as the M of base Trial 1 Link to video explaining how to do the following calculations 0.7138 1.15 18.97 Try 1: ✔ 17.82 2 2 Info ID41 NG 6 Info ID51 Trial 1 5.00 1.98 21.97 NG 2 Info ID121 NG 6 Info ID131The molarity of a solution is determined by four separate titrations or replicates, where the obtained data was 0.4120, 0.4920, 0.3920, and 0.4320 M. Calculate the standard error of the mean for the above data. O 0.00185 O 0.02160 O 0.43200 O 0.04320 O 0.01080
- You are preparing a 100.0 mL standard solution needed for titration analysis. The NaOH (40 g/mol) pellets are measured to be 0.5341 g in a balance with acceptable uncertainty of +0.001 g. Mass of the pellets is recorded after taring the container. The pellets are put in a beaker and added with 50 ml distilled water measured by a graduated cylinder. The solution is then quantitatively transferred to a 100-mL volumetric flask with uncertainty of ±0.08 mL and diluted to a 100-mL mark. What is the concentration (M) of the solution and estimate its uncertainty by propagation? Assumption: There is no uncertainty in molar mass. Express your answer as C+/- u M.How long (in seconds) does it take for the concentration of A to decrease to 0.00800 M? Enter your answer with one decimal place and no units. 1/[A] 120 100 80 60 40 20 0 0 10 20 y = 0.7957x + 61.714 R² = 0.9998 30 Time (sec) 40 50 60If 2.0 × 10-4 moles of H2O2H2O2 in 50 mL solution is consumed in 3 minutes and 25 seconds, what is the rate of consumption of H2O2H2O2? Express the rate in mol per liter·second to two significant digits.
- A commercial research organization is planning to develop a sensor to detect methyl parathion that may be injected into a water supply by terrorists. The LD50 for methyl parathion is reported to be as low as 6 mg ・ kg−1 for rats. They are assuming a safety factor of 1 × 105 and a volume of liquid ingested equal to a cup of coffee (about 250 mL) in the design of the instrument. What concentration (in mg ・ L−1) must their instrument be able to detect? Using Equation 6–10, the concentration you have calculated, the ingestion rate of 250 mL, an exposure frequency of one day, and exposure duration of one day, an adult malebody weight, and an averaging time of 1 day, estimate the hazard index. The RfD for methyl parathion is 2.5 × 10−4 mg ・ kg−1 ・ d−1 .A volumetric calcium analysis on triplicate samples of the blood serum of a patient believed to be suffering from a hyperparathyroid condition produced the following data: mmol Ca/L = 3.55, 3.65, 3.14. What is the 95% confidence interval for the mean of the data, assuming(a) No prior information about the precision of the analysis?(b) s → σ = 0.056 mmol Ca/L?Construct the expression for Kc for the following reaction. 1 3NO(g) = N20(g) + NO2(g) Construct the expression for Kc for the following reaction. 2 X 4HCI(aq) + O2(g) = 2H20(1) + 2C12(g) > Construct the expression for Kc for the following reaction. 3 CH4(g) + 2H2S(g) = CS2(g) + 4H2(g) Construct the expression for Kc for the following reaction. 4 X 2Cu*(aq) + Zn(s) = 2Cu(s) + Zn²*(aq) >