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States of Matter
The substance that constitutes everything in the universe is known as matter. Matter comprises atoms which in turn are composed of electrons, protons, and neutrons. Different atoms combine together to give rise to molecules that act as a foundation for all kinds of substances. There are five states of matter based on their energies of attraction, namely solid, liquid, gases, plasma, and BEC (Bose-Einstein condensates).
Chemical Reactions and Equations
When a chemical species is transformed into another chemical species it is said to have undergone a chemical reaction. It consists of breaking existing bonds and forming new bonds by changing the position of electrons. These reactions are best explained using a chemical equation.
Step by step
Solved in 3 steps with 2 images
- The first step of the mechanism is given in the sketch box below. Modify the given drawing of the product as needed to show the intermediate that is formed in this step (based on the provided curved arrows). Use the +/- tools to add/remove charges, and use the single bond tool to interconvert between double and single bonds. H₂C 2 P Edit Drawing H₂Cow the mechanism for the following reaction conducted at -5 °C in CC14: cyclohexene + bromine yields a dibromocyclohexane Draw structures - including charges and electrons - and add curved arrows. Details count. Step 1 Add three curved arrows to the first step. Draw the step 1 products: 1 organic species; 1 inorganic species. Step 2 • Reproduce the step 1 products. Add two curved arrows to show the bromide ion reacting with the organic species. Draw the final product. 1L o ↑ MapWhat is the Potential energy diagram for this reaction. Pls draw with as much detail as possible. labels and scale) 2-methylpropan-2-ol ---> 2-methylpropene +H2O Draw the potential energy diagram for the reaction of 2-methylpropan-2-ol ---> 2-methylpropene + H20 (1) Label the structures of the (a) reactants, (b) intermediates, (c) transition states, (d) products, and (e) activation energies (E.) for each step. (2) Which step is the rate-determining step? (3) Identify the electrophile and nucleophile in each step when applicable.
- Draw a mechanism for this reaction. H₂C- CH3 -0- Interactive 3D display mode -CH3 H₂C CH₁₂ H₂C-O i Edit the reaction by drawing all steps in the appropriate boxes and connecting them with reaction arrows. Add charges where needed. Electron flow arrows should start on an atom or a bond and should end on an atom, bond, or location where a new bond should be created.Part A Draw a reasonable mechanism for this reaction. Interactive 3D display mode Ph Ph -P=CH, CH2 Ph Edit the reaction by drawing all steps in the appropriate boxes and connecting them with reaction arrows. Add charges where needed. Electron flow arrows should start on an atom or a bond and should end on an atom, bond, or location where a new bond should be created. D 5 C Q Q Q H x" iim H CI Br P F P Pearsonb) Identify A and B and provide mechanism of the reaction. NH2 HONO heat A `CO2H H;CO,C
- 5a) Draw the product(s) of the reaction shown below. Additionally, identify the nucleophile, electrophile and leaving group.2. Show the organic product formed when methyl propanoate is reacted with lithium diisopropyl amide, then methyl ethanoate is slowly added to the mixture. The mixture is neutralized with aqueous acid to obtain a neutral product. (A) Show the steps in the mechanism as reactant is converted to final product. show appropriate arrow pushing and any charges. (B) Draw a box around the final product.Mechanism. Provide the complete mechanism for the reaction below. You must include appropriate arrows, intermediates, and formal charges. میلیم OH u o OH NH 2. Heat
- 027 In Part 1 add the curved arrows to the nucleophilic acyl substitution reaction mechanism. In Part 2, answer the multiple-choice question about the reaction in Part 1. Part 1 4 See Periodic Table O See Hint :0: :Br: Add the missing curved arrow notation. S CI Br Part 2 Which statement is most correct regarding the equilibrium for the above reaction? Choose one: O The equilibrium favors the right (i.e., Kea > 1) because acetate is a better leaving group than bromide. O The equilibrium favors the right (i.e., Kea > 1) because bromide is a better leaving group than acetate. O The equilibrium favors the left (i.e., Keq« 1) because acetate is a better leaving group than bromide. O The equilibrium favors the left (i.e., Keg 1) because bromide is a better leaving group than acetate. +Use the dropdown menu to indicate whether the rate of the reaction shown below will increase, decrease, or remain the same when the reaction conditions are changed to X or to Y or to Z (see below). NaN3 'N3 Br CH3CN X: Change the leaving group from Br to CI Y: Increase the concentration of haloalkane Z: Increase the concentration of NaN3 X: choose your answer.. ^ Y: choose your answer... V Z: choose your answer... choose your answer... Remain the same Nex Decrease IncreaseCurved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic steps. Be sure to account for all bond-breaking and bond-making steps. H H y H H ✪ I CH3OH heat CH3OH heat HH H : Br: O CH3OH heat Drawing Arrows