asap plss thsnkassss dsadadawdafa Given the following at 25 °C and 1.00 atm:2Fe(s) + 02(g) → 2FEO(s)4Fe(s) + 302(g) → 2FE2O3(s)AH° = -544.0 kJAH° = -1648.8 kJ3Fe(s) + 202(g) → Fe304(s)AH° = -1118.4 kJCalculate the AH for the reaction below at 25 °C.Fe203(s) + FeO(s) → Fe304(s)a. -1074.0 kJb.249.8 kJC. -22.0 kJd. 22.2 kJO e. 1074.0 kJ

Given data : Required equation: Fe2o3(s) + FeO (s) -------> Fe3o4(s) Calculate ∆H° = ?

Given the following at 25 °C and 1.00 atm: 2Fe(s) + 02(g) → 2FEO(s) 4Fe(s) + 302(g) → 2Fe2O3(s) AH° = -544.0 kJ %3D AH° = -1648.8 kJ %3D 3Fe(s) + 202(g) → Fe304(s) AH° = -1118.4 kJ %3D Calculate the AH for the reaction below at 25 °C. Fe203(s) + Fe0(s) → Fe304(s) a. -1074.0 kJ b.249.8 kJ C. -22.0 kJ d. 22.2 kJ e. 1074.0 kJ

Given the following at 25 °C and 1.00 atm: 2Fe(s) + 02(g) → 2FEO(s) 4Fe(s) + 302(g) → 2Fe2O3(s) AH° = -544.0 kJ %3D AH° = -1648.8 kJ %3D 3Fe(s) + 202(g) → Fe304(s) AH° = -1118.4 kJ %3D Calculate the AH for the reaction below at 25 °C. Fe203(s) + Fe0(s) → Fe304(s) a. -1074.0 kJ b.249.8 kJ C. -22.0 kJ d. 22.2 kJ e. 1074.0 kJ

Chemistry

9th Edition

ISBN:9781133611097

Author:Steven S. Zumdahl

Publisher:Steven S. Zumdahl

Chapter6: Thermochemistry

Section: Chapter Questions

Problem 73E: Given the following data 2O3(g) 3O2(g)H = 427 kJ O2(g) 2O(g)H = 495 kJ NO(g) + O3(g) NO2(g) +...

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