Given resistors R₁ = 1k, R₂ = 2k, and current source l₁ = 1mA. The Thevenin equivalent voltage measured between "port a" and "port b" in figure 3 is V?
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- Using Thevenin’s theorem, determineRTHand VTHat terminals a-b of for circuits in Figure 3 (a). I need help with this problem, please show all the stepsFor the circuit shown ,IC2 = 1mA ,VCE1 = 2V , and VCE2 = 8V 1. The value of RC is equal to ohm 2. The value of R1 is equal to ohm 3. The value of R2 is equal to ohmFor the circuit shown in Figure Q2ai, drain current In is 2.26 mA and drain to source voltage VDs is 5.22V. Calculate the values of VDD and VD? Q2ai) VDD RD 2kQ •VD Q1 RG ς1 2ΜΩ RS 1kQ Figure Q2ai
- Which of the following statements are correct for the circuit below? Thanks to the capacitors I – C1 and C2, the voltage gain of the circuit increases. II – Capacitors C1 and C2 are coupling capacitors and provide an isolation function between AC and DC voltages in the circuit. Thanks to the III – RE resistor, the voltage gain of the circuit increases. Thanks to the IV – RE resistor, the stability of the circuit increases. The V – C3 Capacitor is a bypass capacitor and prevents the loss of voltage gain. Capacitor VI – C3 is a coupling capacitor and has no effect on the voltage gain in the circuit. VII – As the value of the source internal resistance Rs increases, the voltage gain decreases. VIII – The voltage gain decreases as the value of any RL load to be added to the circuit increasesPt A 6v battey, delivrers loMA to thvee resistors in faralkl, R, =1kr,R2 =2K2,R3=Rx- Calcalate: a) Current in b) Power dissipatiod by Rx and R,-[Anss 6mw, 36mn. c) Resistance ratio Rx/R--(Ans: 6/)- d) Current ratio Ii/Ix. Anst 6/4). Rx stheatis Ix Anss 1 mÁ)Q2. I- For the voltage divider circuit below, (R1 = R2 = R3 = 10 kN, R4 = R5 =1 kn, Vi = 15V), (ZD1 & ZD2 are Zener diodes, zener voltage = 5.6 V) LED 1 and LED 2 are light emitting diodes R1 R2 R3 Vi ZD1 ZD2 LED1 LED2 R4 R5 I. What is the status of each LED (ON or OFF), LED1 ---- ON ----- LED 2 ----- OFE II. What is the current in R4 5 x 10-3 --. III. What is the purpose of resistors R4 and R5, ------ current limiter ----
- V1= 1.5Vkn=0.25mA/V2Find Q-pointFor given value of the circuit, Vsupply = 120 V, and with R₁= 2002, R₂=30.0, R3=75, R4=30N, R5= 200, R6-400 and R7=12002? • What is the voltage drop across Ro? 1. a) 32 V b) 48V c) 100V d) 120V 2. 48 Volts 100 Volts 32 Volts 120 Volts V1 120 V R1 ww 2002 R3 750 R7 12002 R6 m 40Q R2 2300 R4 30Q R5 2200For circuit shown in Figure B16i, calculate, i. IDI ii. ID2 R2 7 kQ D2 Ge Io2 R1 10KQ D1 Ge lo1 .V1 V2 12 v 10 v Figure B16i
- Estimate voltage E2 when E1=90sin2400t V, R1=R2=20 ohms, L1= L2=3mH and M=0.15mH%3D ) Drurde (l0o1102 and (o150 100 + VA- a -4V AVA -7V 81. B b Figure 2 shows a simplified model of a gas-discharge lamp. One characteristic of these lamps is that they exhibit negative resistance; in other words, as current increases the voltage drops further, making such lamps inherently unstable. As such, a current-limiting ballast is required. For the connection shown in the figure: 1. Find the equivalent Thevenin circuit of the lamp. 2. Find the ballast resistance needed to limit the current drawn from a 24-volt source to 6 amperes.