G: st = 38.92-17.59 FN = (90kg ) (9.8 m/s²) = 21.35 = 882w R: a =?, MK = ? A: FF ↑ Ev=Fg [40 Kay + 50kg |= 40 ку FA=SOON

University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter6: Applications Of Newton's Laws
Section: Chapter Questions
Problem 41P: A roller coaster car starts from rest at the top of a track 30.0 m long and inclined at 20.0to the...
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I was able to do the given, required and analysis. Can you please show me a solution
G: At = 38.92-17·59 FN = (90kg ) (9.8 m³5²)
= 21.35
= 882 N
R: a =?, MK = ?
A:
F
↑Fo=Fg
показ
+ 50kg
1 = 90kg
J Fg
FA=500N
Transcribed Image Text:G: At = 38.92-17·59 FN = (90kg ) (9.8 m³5²) = 21.35 = 882 N R: a =?, MK = ? A: F ↑Fo=Fg показ + 50kg 1 = 90kg J Fg FA=500N
Speed
0.0 m/s
50 kg
Let me know IF there is enough information to calculate the coefficient of kinetic friction.
I can only tell you that the applied force is 500 N.
IF
you can calculate the coefficient of kinetic friction, show me using GRASS.
IF you do not have enough information, make an assumption that would help you solve for the
coefficient of kinetic friction.
40 kg
Transcribed Image Text:Speed 0.0 m/s 50 kg Let me know IF there is enough information to calculate the coefficient of kinetic friction. I can only tell you that the applied force is 500 N. IF you can calculate the coefficient of kinetic friction, show me using GRASS. IF you do not have enough information, make an assumption that would help you solve for the coefficient of kinetic friction. 40 kg
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