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From the data given below, construct relevant portion of the predominance area dia- gram of the Mo-S-O system at 1000 K: 1. 2SO2(g) S2(g) +202(g), 2. MoS2(s) = Mo(s) + S₂(g), 3. MoO2(s) Mo(s) + O2(g), 4. MoO3(s) MoO2(s) + O2(g), AG=173,240-34.627 cal AG=85,870-37.33T cal = AG3 140,500+4.67 log T-56.8T cal AG4=38,700-19.5T cal

From the data given below, construct relevant portion of the predominance area dia- gram of the Mo-S-O system at 1000 K: 1. 2SO2(g) S2(g) +202(g), 2. MoS2(s) = Mo(s) + S₂(g), 3. MoO2(s) Mo(s) + O2(g), 4. MoO3(s) MoO2(s) + O2(g), AG=173,240-34.627 cal AG=85,870-37.33T cal = AG3 140,500+4.67 log T-56.8T cal AG4=38,700-19.5T cal

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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From the data given below, construct relevant portion of the predominance area dia- gram of the Mo-S-O system at 1000 K: 1. 2SO2(g) S2(g) +202(g), 2. MoS2(s) = Mo(s) + S₂(g), 3. MoO2(s) Mo(s) + O2(g), 4. MoO3(s) MoO2(s) + O2(g), AG=173,240-34.627 cal AG=85,870-37.33T cal = AG3 140,500+4.67 log T-56.8T cal AG4=38,700-19.5T cal
Transcribed Image Text:From the data given below, construct relevant portion of the predominance area dia- gram of the Mo-S-O system at 1000 K: 1. 2SO2(g) S2(g) +202(g), 2. MoS2(s) = Mo(s) + S₂(g), 3. MoO2(s) Mo(s) + O2(g), 4. MoO3(s) MoO2(s) + O2(g), AG=173,240-34.627 cal AG=85,870-37.33T cal = AG3 140,500+4.67 log T-56.8T cal AG4=38,700-19.5T cal
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