For the series-parallel network below caluate the following. Express your answer in polar notation + V₂ Xc, 18 Ω 1₂ 13 th₁202 12 Ω E = 12 V 20º Z₁ = |= 4₁ = 1₂= 13 = VL = I moo X = 6 Ω I ZT 7 V 2 V 2 Xc₂ ° units ° units units units units ° units
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- 0 !!! a *Further Engineering Mathematic X + File | C:/Users/user/Downloads/Further%20Engineering%20MathematicsAssignment-2.pdf Draw T Read aloud CD 9. The two complex numbers V and W represent two reactances connected in series. Calculate the total reactance by finding their sum. AF 3+j4 B = 4-j5 C = 5-j2 D=1-j3 E = 2 +j3FF" FF 4+j1 3 of 4 10. The complex numbers V and W represent two force vectors. Place them on an Argand diagram and calculate the difference between them. 11. Use your given values of V and W to represent the reactances Z₁, Z₂ (as shown in the circuit diagram). Calculate the current flowing in the circuit in polar form if the voltage is v = 1220° and V i = ZTotal Z₁ Z₂ o J (¹) ENG T 60 11:16 PM 3/17/2023 xQUESTION 3 An inductor, a capacitor, and a resistor are connected in parallel with a function generator. The inductor draws 100mA RMS, the capacitor draws 150mA RMS, and the resistor draws 200mA RMS. Find the magnitude of the total current. O 450mA RMS O 544mA RMS O 352mA RMS O 206mA RMS67% 4 a M 4 O 6:25 8 docs.google.com/forms/d/e. O The name, email, and photo associated with your Google account will be recorded when you upload files and submit this form Questions Z1=j5 Z2=-j5 Z3=-j7 Z4=18-j9 Z5=1-jó Z6=11+j5 Vs1=20sin(wt-70) Vs2=80 cos(wt-35) Vs3-15 cos (wt-5O) Find the complex power supplied by all sources? V52 14 Vs, O 26 1 Add file Back Submit Clear form Never submit passwords through Google Forms. This form was created inside of University of Kirkuk. Report Abuse العربية الإنجليزية
- 9. The matiueonk shawn is aparastineg the steady state with simusaielal un ualtage saunces. i v= 2cos 2t amd N2 = 2 sim 2+ , diturmine the valtage VaCt). 3173 F 2173 F Ja 2173F 31H allFind the current through the load in polar form. R1 L1 R3 C1 100 150MH 250 30uF E E1 502 120 Vms 150 Vrms 60 Hz 60 Hz 30 45° 250m HThe circuit shown in figure EM1-1 shows an AC voltage source VAC connected in series with a load that has • resistance R=280 Ohms, inductance L=1.1mH, and • capacitance C=4.7mF. Calculate values of, and select the apporpriate answer from the list from the list below for • the frequency, fres (in Hz) of the AC source that results in resonance in the load and the impedance, Zres (in Ohms) of the load at this frequency. ● Resonant Frequency, fres= ✓ Hz Impedance of the Load at Resonance, Zres= R 280 Ω ✓ Ohms V. AC L 4.7 mF 1.1 mH Figure EM1-1 Downloadable image
- Please show your detailed solution Number 14 The current in a series inductive circuit is 7.5 A at 25 Hz. The circuit takes 425 W, and the power factor is 0.47. The resistance of the circuit is A. 7.32 ohms C. 7.98 ohms B. 7.86 ohms D. 7.56 ohms4. A capacitor now is connected in parallel with R1 to reduce the ripple. Find the value of the capacitance needed to make the following ripple index less than 5% through PSpice simulation study. V -×100% -V o,min 0,max rpp RFP = -x100% = V dc dc D1 Dbreak R1 V1 1k VAMPL = 169.71 FREQ = 50 VoFind the impedance Zab in the circuit seen in figure. Suppose that R = = 4.5 2. Part A Zab = Part B Ω Zab Zab R ww Ω -182 카 ZAN 20 M Express Zab in polar form. Express your answer in ohms to three significant figures. Enter your answer using angle notation. Express argument in degrees. ANSWER: 40 0 Express Zab in rectangular form. Express your answer in ohms to three significant figures. Enter your answer in rectangular form. ANSWER: m 102 -/200 j200
- Use nodal analysis to find Io. -j2N 6290°v j5N 220° AÀ -j1QQ.2: Solve the following determinate. Then, simplify the complex numbers to find x and y values (the separated real and imaginary value). (Note: Check the answer by the caleulator) 18 - 6i 5230 2i V- -3i 3 - 4iSolve the power triangle at Z6 in the circuit diagram below.V1, V2, and V3 = 220∠0°, 50 HzZ1 = 7+j8 ohmsZ2 = 6+j3 ohmsZ3 = 5+j5 ohmsZ4 = 2+j3 ohmsZ5 = 8+j4 ohmsZ6 = 1+j9 ohms