For the reaction SbCl5(g) → SbCl3(g) + Cl₂(g), AG°f (SbCl5) = -334.34 kJ/mol AG°f (SbCl3) = -301.25 kJ/mol AHᵒf (SbC15) = -394.34 kJ/mol AHᵒf (SbC13) = -313.80 kJ/mol Calculate the value of the equilibrium constant (Kp) at 800 K and 1 atm pressure. O 1.31 x 10³ O 1.91 x 10² O 1.11 x 10³ O None of the above 1.71 x 10²

Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
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Chapter18: Principles Of Chemical Reactivity: Entropy And Free Energy
Section: Chapter Questions
Problem 38PS: For the reaction TiCl2(s) + Cl2(g) TiCl4(), rG = 272.8 kj/mol-txn. Using this value and other data...
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For the reaction SbCl5(g) → SbCl3(g) + Cl₂(g),
AG°f (SbCl5) = -334.34 kJ/mol
AG°f (SbC13) = -301.25 kJ/mol
AHᵒf (SbC15) = -394.34 kJ/mol
AHᵒf (SbC13) = -313.80 kJ/mol
Calculate the value of the equilibrium constant (Kp) at 800 K and 1 atm pressure.
O 1.31 x 103
O 1.91 x 10²
O 1.11 x 10³
O None of the above
O 1.71 x 10²
Transcribed Image Text:For the reaction SbCl5(g) → SbCl3(g) + Cl₂(g), AG°f (SbCl5) = -334.34 kJ/mol AG°f (SbC13) = -301.25 kJ/mol AHᵒf (SbC15) = -394.34 kJ/mol AHᵒf (SbC13) = -313.80 kJ/mol Calculate the value of the equilibrium constant (Kp) at 800 K and 1 atm pressure. O 1.31 x 103 O 1.91 x 10² O 1.11 x 10³ O None of the above O 1.71 x 10²
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