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- F4-25. Replace the loading system by an equivalent resultant force and couple moment acting at point A. 100 Ib - 200 Ib 3n 3t 150 lb Prob. F4-25F4-27. Replace the loading system by an cquivalent resultant force and couple moment acting at point A. 900 N\30 300 N 300 N-m 0.75 mT0.75 m 0.75 mT 0.75 m Prob. F4-2733. Consider a net force, Fnet 20i - 40j N acting on a 10 kg object. The objęct's initial velocity is, vo = -4i - 6j m/s. Please finish the vector equations in the table below, Vector i i Fuet 20 -40 a Vo -4 -6 V D
- 7. Two forces F1 and F2 are applied to a post as shown. Write the resultant force in terms of magnitude and coordinate direction angles Fl-S kN (a, B, v). 60 Ans. FR = 3.85 kN, a = 49.57°, B =66.52°, Fal - 2 kN 45 v = 49.57Each propeller of the twin-screw ship develops a full-speed thrust of F=315 kN. In maneuvering the ship, one propeller is turning full speed ahead and the other full speed in reverse. What thrust Pmust each tug exert on the ship to counteract the effect of the ship's propellers? Assume a -40 m,b-136 m.c-14 m. Answer: P-i D÷ kN10.Which one of the statements is NOT true about vectors? () A A If ass, where a is acceleration and v is velocity, then does not change in magnitude. B If a forcerhas an x component--25N and y component -40N , Fmakes an acute angle with +x-axis. C C If two vectors have unequal magnitudes, their sum can never be zero.
- 2- N.F. is the strongest force in the body. true O false3. Three tugboats are used to bring a large ship to a pier as shown. Each tugboat exerts a 4000 Ib force pushing toward the large ship. Determine an equivalent force and couple system at point A. 1 looft. looft 150 fA /s0 ft 100 t 5off A 50ft 95° O a. Equivalent Force = 6030å-3570ĝ lb Equivalent Moment = -1, 150, 000k ft-lb b. Equivalent Force = 5230å-43703 lb Equivalent Moment = -1, 190, 000k ft-lb O c. Equivalent Force = 6030å-3570ĝ Ib Equivalent Moment = 1, 150, 000k ft-lb d. None of the above20. The block has a mass of 60 kg. The coefficient of static friction is 0.3. The minimum force, P (N) required to hold the crate from sliding is: O O O A. 91 60 kg 8 = 40° B. 184 C. 253 D. 338