earning Goal: To understand the meaning and the basic applications of PV diagrams for an ideal gas. As you know, the parameters of an ideal gas are described by the equation PV = nRT, where p is the pressure of the gas, V is the volume of the gas, n is the number of moles, R is the universal gas constant, and T is the absolute temperature of the gas. It follows that, for a portion of an ideal gas, PV = constant. One can see that, if the amount of gas remains constant, it is impossible to change just one parameter of the gas: At least one more parameter would also change. For instance, if the pressure of the gas is changed, we can be sure that either the volume or the temperature of the gas (or, maybe, both!) would also change. To explore these changes, it is often convenient to draw a graph showing one parameter as a function of the other. Although there are many choices of axes, the most common one is a plot of pressure as a function of volume: a pV diagram. Review One important use for pV diagrams is in calculating work. The product pV has the units of Pax m³ = (N/m²). m³ N·m = J; in fac absolute value of the work done by the gas (or on the gas) during any process equals the area under the graph corresponding to that proce diagram. If the gas increases in volume, it does positive work; if the volume decreases, the gas does negative work (or, in other words, worl done on the gas). If the volume does not change, the work done is zero. The following questions may seem repetitive; however, they will provide practice. Also, the results of these calculations may be helpful in th of the problem. ▼ Part A Calculate the work W done by the gas during process 1-2. Express your answer in terms of po and Vo. W = - ΑΣΦ VO ?

College Physics
1st Edition
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter13: Temperature, Kinetic Theory, And The Gas Laws
Section: Chapter Questions
Problem 27PE: In the text, it was shown that N/V=2.681025m3 for gas at STP. (a) Show that this quantity is...
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Learning Goal:
To understand the meaning and the basic applications of PV
diagrams for an ideal gas.
As you know, the parameters of an ideal gas are described by
the equation
PV = nRT,
where p is the pressure of the gas, V is the volume of the
gas, n is the number of moles, R is the universal gas
constant, and T is the absolute temperature of the gas. It
follows that, for a portion of an ideal gas,
One can see that, if the amount of gas remains constant, it is
impossible to change just one parameter of the gas: At least
one more parameter would also change. For instance, if the
pressure of the gas is changed, we can be sure that either the
volume or the temperature of the gas (or, maybe, both!) would
also change.
To explore these changes, it is often convenient to draw a
graph showing one parameter as a function of the other.
Although there are many choices of axes, the most common
one is a plot of pressure as a function of volume: a pV
diagram.
Figure
pV
T
In this problem, you will be asked a series of questions
related to different processes shown on a pV diagram (Figure
1). They will help you become familiar with such diagrams
and to understand what information may be obtained from
them.
3po
2po
= constant.
Po
5:
4
6:
Vo 2V 3V
1 of 1
Review | Constants
One important use for pV diagrams is in calculating work. The product pV has the units of Pa × m³ = (N/m²) · m³ =
=N·m = J; in fact, the
absolute value of the work done by the gas (or on the gas) during any process equals the area under the graph corresponding to that process on the pV
diagram. If the gas increases in volume, it does positive work; if the volume decreases, the gas does negative work (or, in other words, work is being
done on the gas). If the volume does not change, the work done is zero.
The following questions may seem repetitive; however, they will provide practice. Also, the results of these calculations may be helpful in the final section
of the problem.
Part A
Calculate the work W done by the gas during process 1-2.
Express your answer in terms of po and Vo.
ΨΕ ΑΣΦ
W =
Submit
Previous Answers Request Answer
X Incorrect; Try Again; 2 attempts remaining
Your answer either contains an incorrect numerical multiplier or is missing one.
Part B Complete previous part(s)
Part C Complete previous part(s)
Part D Complete previous part(s)
Part E Complete previous part(s)
Part F Complete previous part(s)
?
Part G Complete previous part(s)
Transcribed Image Text:Learning Goal: To understand the meaning and the basic applications of PV diagrams for an ideal gas. As you know, the parameters of an ideal gas are described by the equation PV = nRT, where p is the pressure of the gas, V is the volume of the gas, n is the number of moles, R is the universal gas constant, and T is the absolute temperature of the gas. It follows that, for a portion of an ideal gas, One can see that, if the amount of gas remains constant, it is impossible to change just one parameter of the gas: At least one more parameter would also change. For instance, if the pressure of the gas is changed, we can be sure that either the volume or the temperature of the gas (or, maybe, both!) would also change. To explore these changes, it is often convenient to draw a graph showing one parameter as a function of the other. Although there are many choices of axes, the most common one is a plot of pressure as a function of volume: a pV diagram. Figure pV T In this problem, you will be asked a series of questions related to different processes shown on a pV diagram (Figure 1). They will help you become familiar with such diagrams and to understand what information may be obtained from them. 3po 2po = constant. Po 5: 4 6: Vo 2V 3V 1 of 1 Review | Constants One important use for pV diagrams is in calculating work. The product pV has the units of Pa × m³ = (N/m²) · m³ = =N·m = J; in fact, the absolute value of the work done by the gas (or on the gas) during any process equals the area under the graph corresponding to that process on the pV diagram. If the gas increases in volume, it does positive work; if the volume decreases, the gas does negative work (or, in other words, work is being done on the gas). If the volume does not change, the work done is zero. The following questions may seem repetitive; however, they will provide practice. Also, the results of these calculations may be helpful in the final section of the problem. Part A Calculate the work W done by the gas during process 1-2. Express your answer in terms of po and Vo. ΨΕ ΑΣΦ W = Submit Previous Answers Request Answer X Incorrect; Try Again; 2 attempts remaining Your answer either contains an incorrect numerical multiplier or is missing one. Part B Complete previous part(s) Part C Complete previous part(s) Part D Complete previous part(s) Part E Complete previous part(s) Part F Complete previous part(s) ? Part G Complete previous part(s)
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