Each shot of the laser gun most favored by Rosa the Closer, the intrepid vigilante of the lawless 22nd century, is powered by the discharge of a 1.67 F capacitor charged to 52.9 kV. Rosa rightly reckons that she can enhance the effect of each laser pulse by increasing the electric potential energy of the charged capacitor. She could do this by replacing the capacitor's filling, whose dielectric constant is 487, with one possessing a dielectric constant of 985. Find the electric potential energy U₁ of the original capacitor when it is charged. Calculate the electric potential energy U₂ of the upgraded capacitor when it is charged. U₁ = U₂. = J J

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter20: Electric Potential And Capacitance
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© Macmillan Learning
Each shot of the laser gun most favored by Rosa the Closer, the intrepid vigilante of the lawless 22nd century, is powered by the
discharge of a 1.67 F capacitor charged to 52.9 kV. Rosa rightly reckons that she can enhance the effect of each laser pulse by
increasing the electric potential energy of the charged capacitor. She could do this by replacing the capacitor's filling, whose
dielectric constant is 487, with one possessing a dielectric constant of 985.
Find the electric potential energy U₁ of the original capacitor
when it is charged.
Calculate the electric potential energy U₂ of the upgraded
capacitor when it is charged.
U₁ =
U₂. =
J
J
Transcribed Image Text:© Macmillan Learning Each shot of the laser gun most favored by Rosa the Closer, the intrepid vigilante of the lawless 22nd century, is powered by the discharge of a 1.67 F capacitor charged to 52.9 kV. Rosa rightly reckons that she can enhance the effect of each laser pulse by increasing the electric potential energy of the charged capacitor. She could do this by replacing the capacitor's filling, whose dielectric constant is 487, with one possessing a dielectric constant of 985. Find the electric potential energy U₁ of the original capacitor when it is charged. Calculate the electric potential energy U₂ of the upgraded capacitor when it is charged. U₁ = U₂. = J J
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