During astronaut training, the person rides a simulated rocket, accelerating from rest to maximum velocity of 1038 km/h in 5.00 s and then stopped in only 1.8 s. If the acceleration opposite to the direction of motion is Xg, what is X?
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- An object moves along the x axis according to the equation x = 3.00t2 2.00t + 3.00, where x is in meters and t is in seconds. Determine (a) the average speed between t = 2.00 s and t = 3.00 s, (b) the instantaneous speed at t = 2.00 s and at t = 3.00 s, (c) the average acceleration between t = 2.00 s and t = 3.00 s, and (d) the instantaneous acceleration at t = 2.00 s and t = 3.00 s. (e) At what time is the object at rest?During astronaut training, the person rides a simulated rocket, accelerating from rest to maximum velocity of 947 km/h in 5.00 s and then stopped in only 1.5 s. If the acceleration opposite to the direction of motion is Xg, what is X? (g is the acceleration due to gravity)My question isn't how to solve the problem exactly. In fact, it's already been solved on this website. My question is about the acceleration. When I solve this problem myself, first I calculate the velocity by dividing 100m by 53s. I get 1.89m/s. Then I use that to find the acceleration using the equation vf = vi + at. That's 1.89/53 = 0.036m/s^2. That's not correct. The correct way to find the acceleration is to us the equation d = 1/2 at^2 and solve that way without taking the intermediate step of finding the velocity. Doing it that way, the acceleration is 0.0712m/s^2. My question is why you get a different result doing it the first way than you get doing it the second way.
- An article explains that the locomotion of different-sized animals can be compared when they have the same Froude number, defined as F = gl velocity, g is the acceleration due to gravity (9.81 m/sec2) and I is the animal's leg length. (a) Different animals change from a trot to a gallop at the same Froude number, roughly 2.56. Find the velocity at which this change occurs for an animal with a leg length of 1.12 m. (b) Ancient footprints of a dinosaur are roughly 1.4 m in diameter, corresponding to a leg length of roughly 5.6 m. By comparing the stride divided by the leg length with that of various modern creatures, it can be determined that the Froude number for this dinosaur is roughly 0.025. How fast was the dinosaur traveling? (a) The velocity at which this animal changes change from a trot to a gallop is (Round to the nearest tenth as needed.) where v is the animal's (...) m/sec.Starting from rest, a bus leaves a gas station with a constant acceleration of 2 m/s˄2 until it reaches a speed of 10 m/s. The bus then continues to move with this speed (10 m/s) for 5 s. Then the bus decelerates at 2.5 m/s˄2 until it stops. What is the total distance traveled by the bus? (Answer: 95 m)Problem 5. The velocity of a particle moving along the x -axis is defined by v = kx°- 4x² + 6x , where v is in m/sec, x in meters , and k is constant. If K = 1, compute the value of acceleration after x= 2meters. Find: 10. a = ?
- Problem 2: An object is thrown from the top of a building that is 16.4 m high. The object is thrown with a velocity of 7.3 m/s. Part (a) How high above the ground does the object go? Numeric : A numeric value is expected and not an expression. h = Part (b) How long is it in the air in seconds? Numeric : A numeric value is expected and not an expression. t = Part (c) What is the velocity of the object in m/s after 0.5 s? Numeric : A numeric value is expected and not an expression. v = Part (d) What is the velocity of the object in m/s after 1.5 s? Numeric : Anumeric value is expected and not an expression. V = Part (e) What is the velocity of the object in m/s when it reaches the bottom? Numeric : A numeric value is expected and not an expression. V =A car is traveling east at 17.5 m/s when it turns due north and accelerates to 32.5 m/s, all during a time of 5.00 s. Calculate the magnitude of the car's average acceleration (in m/s2).the rocket starts from rest at t=0 and travel straight up. it's height above the ground as a function of time can be approximated by s=bt^2+ct^3, where b and c are constants. at t=10s, the rocket's velocity and acceleration are v= 229m/s and a=28.2 m/s^2 A.) determine the time in seconds at which the rocket reaches supersonic speed (325 m/s) B.) determine the value of constant B C.) determine the value of constant C
- A parachutist jumps out of an airplane and accelerates with gravity to a maximum velocity of 58.8 m/s in 6 seconds. She then pulls the parachute cord and after a 4 second deceleration, descends at 10 m/s for 60 seconds. reaching the ground. From what height did the parachutist jump?A human-powered vehicle (HPV) team wants to model the acceleration during the 260-m sprint race (the first 60 m is called a flying start) using a = A – Cv, where a is acceleration in m/s2? and v is the velocity in m/s. From wind tunnel testing, they found that C = 0.0012 m-1. Knowing that the cyclist starts from rest and is going 110 km/h at the 260-meter mark, what is the value of A? POSE HULMANA boat running at its top speed takes 3.0 hours to travel 12 km down a river. It then takes 5.0 hours to return to its starting place. What is the velocity of the river? (Answer should look like '0.35 km/h'. I know bad units.)