Demonstrate how males are at an increased risk of sex-linked recessive traits by crossing a female who is a carrier for Hunter syndrome with a normal male. The genotypes involved are XH, Xh, and Y. State the genotypes and phenotypes of the offspring.
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- Demonstrate how males are at an increased risk of sex-linked recessive traits by crossing a female who is a carrier for Hunter syndrome with a normal male. The genotypes involved are XH, Xh, and Y. State the genotypes and
phenotypes of the offspring.
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- Assume that the incidence of an X-linked recessive disorder is 1 in 200 male births. What is the frequency of the mutant allele?An individual with 46, XX genotype is diagnosed with Duchenne-type Muscular Dystrophy, a recessive X-linked disorder. Genetic tests confirm that this individual is a heterozygote for this disorder. Briefly, but specifically, explain how it’s possible that they are showing symptoms of this disorder.A. Color-blindness is a recessive, sex-linked disorder in humans. A color- blind man has a child with a woman who is a carrier of the disorder. KEY: X= normal vision XC = color-blindness 2. Illustrate using a Punnett square the probability of having children who will have normal vision and children who will be color-blind. Guide Questions: a. What is the genotype of the male?. b. What is the genotype of the female? c. What is the chance that the child will be color-blind? d. What is the chance that a daughter will be color-blind? e. What is the chance that a son will be color-blind?
- A male with autosomal dominant brown hair and a female with unknown hair color have 3 sons with recessive blonde hair. What is the male’s genotype? What are the possible genotype(s) and phenotype(s) [hair color] of the female?Sickle cell anemia is inherited as an autosomal recessive condition. It also exhibits incomplete dominance in that the heterozygous genotype displays a mild form of the disease known as sickle cell trait while individuals with the homozygous recessive genotype have a severe form of SCA. A man who has severe sickle cell anemia marries a woman who suffers from a mild trait. What is the probabilitu they will have a child with severe SCA?What is the probability they will have a child with mild SCA? What is the probability they will have a normal child? Show ALL work using punnett squares.The determiner for brown eyes (B) is dominant to blue eyes (b) and is not X-linked. A colorblind man with brown eyes, whose mother was blue-eyed, marries a blue-eyed woman having normal vision, whose father was colorblind. Show the expected phenotypes ratio of their children involving eye color, color blindness, and sex.
- Discuss the differences among sex-influenced, sex-limited, andsex-linked inheritance. Give examples.A man who is a dwarf due to achondroplasia and has normal vision marries a color-blind woman of normal height. The man's father was 6 feet tall, and both the woman's parents were of average height. Achondroplasia is autosomal dominant, and red-green color blindness is X-linked recessive. What are the possible genotypes and phenotypes of their children? What are the ratios for each? For full credit, you must show all work.Define what is a sex-linked disorder? A Bb guinea pig crosses with a Bb guinea pig and four offspring offspring offspring are produced. All of the offspring are black. Explain how this could happen.
- Color blindness is an X-linked recessive disease. A female and a male with normal vision have 4 children. The phenotypes of the children are listed below: 2 Colorblind males, 1 normal vision female, one normal vision male. Given these results, the female must be a carrier for colorblindness. True FalseA gene that controls the ability to see red and green is located on the X chromosome but not on the Y chromosome. There is a recessive nonfunctional allele for this gene that can cause red-green color blindness if the person possessing it does not also have the dominant normal gene. Consider the case of a carrier mother who is heterozygous for the red-green vision gene and a father who has normal vision. Use XB = normal vision, Xb = color-blind vision. What is the chance the parents would have a color-blind boy? A color-blind girl? What about a girl or boy with normal vision? Redo the Punnett square for a carrier mother (XBXb) and a color-blind father (XbY). Do the chances of having color-blind children change? How?In 1-3 sentences define the following heredity types: Autosomal dominant and recessive, X-linked dominant and recessive, epistasis, polygenic, codominant