Consider the following C++ code snippet: int cards[3]; for (int i = 0; i < 3; i++) cards[i] = 0; Choose the best statement: A) This code will compile and run but causes an out-of-range memory write. B) This code will compile and has no apparent issues. C) This code will not compile as written. D) This code shows an example of dynamic memory alloca
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Consider the following C++ code snippet:
int cards[3];
for (int i = 0; i < 3; i++)
cards[i] = 0;
Choose the best statement:
A) This code will compile and run but causes an out-of-range memory write.
B) This code will compile and has no apparent issues.
C) This code will not compile as written.
D) This code shows an example of dynamic memory allocation.
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- X15: inOrder Write a function in Java that implements the following logic: Given three ints, a, b , and c,return true if b is greater than a, and c is greater than b.However, with the exception that if bok is true, b does not need to be greater than a.Consider the following pseudo code, Method func() { PRINT “This is recursive function" func() } Method main( { func() } What will happen when the above snippet is executed?#include <stdio.h>void cubeByReference( int *nPtr ); // function prototypeint main( void ){ int number = 5; // initialize number printf("The original value of number is %d", number ); // pass address of number to cubeByReference cubeByReference( &number ); printf("\nThe new value of number is %d\n", number );} // end main void cubeByReference( int *nPtr ){ *nPtr = *nPtr* *nPtr* *nPtr;} passing argument by reference - We modify the code above 1- define a second argument (example "int number2 = 9") and a pointer to it 2- define a second function (addByReference) that adds number2 to number - passing both arguments by reference 3- print-out the result (that is in number) Upload the output and .c code
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