Consider an imaginary box with dimensions 15 cm × 45 cm × 95 cm. There is an E- field with a uniform magnitude 850 N/C going out through the left side of the box and an E-field with a uniform magnitude 550 N/C going in through the right side, as shown in the figure below. 
 (a) Calculate the total electric flux through the box. 
 
 (b) Use Gauss’s law and your previous answer to find the net charge enclosed by the box.

Physics for Scientists and Engineers: Foundations and Connections
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Chapter25: Gauss’s Law
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Consider an imaginary box with dimensions 15 cm × 45 cm × 95 cm. There is an E- field with a uniform magnitude 850 N/C going out through the left side of the box and an E-field with a uniform magnitude 550 N/C going in through the right side, as shown in the figure below.

(a) Calculate the total electric flux through the box.

(b) Use Gauss’s law and your previous answer to find the net charge enclosed by the box.

1. Consider an imaginary box with dimensions 15 cm × 45 cm x 95 cm. There is an E-
field with a uniform magnitude 850 N/C going out through the left side of the box
and an E-field with a uniform magnitude 550 N/C going in through the right side, as
shown in the figure below.
850
N/C
95
550
cm
N/C
45
cm
15 cm
(a) Calculate the total electric flux through the box.
(b) Use Gauss's law and your previous answer to find the net charge enclosed
by the box.
Transcribed Image Text:1. Consider an imaginary box with dimensions 15 cm × 45 cm x 95 cm. There is an E- field with a uniform magnitude 850 N/C going out through the left side of the box and an E-field with a uniform magnitude 550 N/C going in through the right side, as shown in the figure below. 850 N/C 95 550 cm N/C 45 cm 15 cm (a) Calculate the total electric flux through the box. (b) Use Gauss's law and your previous answer to find the net charge enclosed by the box.
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