Between AB there is a 20 cm aluminum wire that supports a mass of 490 g and between BC anotherbronze cable of length 10 cm that supports a mass of 245 g; where EAL = 0.2x10¹¹ Pa (Young'smodulus) and EBr = 5x10¹¹ Pa; with equal cross sections S = 0.2 cm² determine what lengthreaches point C.A- B-C

To solve the problem depicted in the image you've provided, we will apply the formula for elastic…

Answered: Between AB there is a 20 cm aluminum…

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter14: Static Equilibrium, Elasticity, And Fracture

Section: Chapter Questions

Problem 46PQ: Use the graph in Figure P14.46 to list the three materials from greatest Youngs modulus to smallest....

See similar textbooks

Similar questions

Use the graph in Figure P14.46 to list the three materials from greatest Youngs modulus to smallest. Explain your reasoning. FIGURE P14.46
A large chunk of metal has a mass of 393 kg, and its volume is measured to be 0.05 m3. (a) Find the metal's mass density and weight density in SI units, (b) what kind of metal is it?
(a) The "lead" in pencils is a graphite composition with a Young's modulus of about 1109 N/ m2. Calculate the change in length of the lead in an automatic pencil if you tap it straight into the pencil with a force of 4.0 N. The lead is 0.50 mm in diameter and 60 mm long. (b) Is the answer reasonable? That is, does it seem to be consistent with what you have observed when using pencils?
(a) When water freezes, its volume increases by 9.05% (that is, V/V0=9.05102 ). What force per unit area is water capable of exerting on a container when it freezes? (It is acceptable to use the bulk modulus of water in this problem.) (b) Is it surprising that such forces can fracture engine blocks, boulders, and the like?
A steel rod 55 cm long has a diameter of 30.0 cm. The compressive strength (the maximum stress it can support without breaking) of this steel is 550.0 × 106 N/m2. What is the compression force that would break the rod? Answer in MN (meganewtons)
1-66. Determine the largest load P that can be applied to the frame without causing either the average normal stress or the average shear stress at section a-a to exceed σ = 150 MPa and 7 = 60 MPa, respectively. Member CB has a square cross section of 25 mm on each side. 2 m B -1.5 m- Prob. 1-66 C
PROBLEM 2. The light rigid bar ABCD shown in Fig. P-252 is pinned at B and connected to two vertical rods. Assuming that the bar was initially horizontal and the rods stress-free, determine the stress in each rod after the load after the load P = 41. 29 KN is applied. Hint: convert the distance of each member into mm, area of steel and aluminum into mm^2, & E into MPa.. Steel L-3 ft A- 0.5 in E- 29 x 10° psi 4 ft Aluminum L-4ft A- 0.75 in E - 10 x 10 psi + 2 ft Figure P-252
Problem 1 ▪5-1. A shaft is made of a steel alloy having an allowable shear stress of Tallow = 12 ksi. If the diameter of the shaft is 1.5 in., determine the maximum torque T that can be transmitted. What would be the maximum torque T' if a 1-in.-diameter hole is bored through the shaft? Sketch the shear-stress distribution along a radial line in each case. T
Q1. An experiment was conducted in order to find the fracture toughness of a composite material. The resulting force values for different crack lengths are given in the table. a (crack length, mm) F (Force, N) 0.1 400 0.2 455 0.3 483 0.4 510 0.5 535 Find a linear expression for the force versus crack length using the best line as F(a)— с1 а + с2
A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. Let us first derive the expression for the tension. By Newton's First Law ΣF = the components of force that makes this so is ΣF = T - = 0 Simplifying this results to T = g/(ϕ) Analyzing the figure above, we arrive at (ϕ) = sqrt( 2 + ) / ( / + ) By substitution, we arrive at the following: T = ( + 2 ) g / ( sqrt ( 2 + ) ) If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T = 0.370 N
Suppose a piano tuner stretches a steel piano wire 8.5 mm. The wire was originally 0.925 mm in diameter, 1.29 m long, and has a Young's modulus of 2.10 × 1011 N/m2.Randomized Variablesl0 = 1.29 ml = 8.5 mmd = 0.925 mm Calculate the force a piano tuner applies to stretch the steel piano wire in Newtons.
Calculate the force (in N) a piano tuner applies to stretch a steel piano wire 8.20 mm, if the wire is originally 0.850 mm in diameter and 1.35 m long. N t

SEE MORE QUESTIONS

Recommended textbooks for you

Physics for Scientists and Engineers: Foundations…

Physics

ISBN:

9781133939146

Author:

Katz, Debora M.

Publisher:

Cengage Learning

College Physics

Physics

ISBN:

9781938168000

Author:

Paul Peter Urone, Roger Hinrichs

Publisher:

OpenStax College

Inquiry into Physics

Physics

ISBN:

9781337515863

Author:

Ostdiek

Publisher:

Cengage

Physics for Scientists and Engineers: Foundations…

Physics

ISBN:

9781133939146

Author:

Katz, Debora M.

Publisher:

Cengage Learning

College Physics

Physics

ISBN:

9781938168000

Author:

Paul Peter Urone, Roger Hinrichs

Publisher:

OpenStax College

Inquiry into Physics

Physics

ISBN:

9781337515863

Author:

Ostdiek

Publisher:

Cengage

Physics for Scientists and Engineers, Technology …

Physics

ISBN:

9781305116399

Author:

Raymond A. Serway, John W. Jewett

Publisher:

Cengage Learning

SEE MORE TEXTBOOKS