At a particular instant, a 1.0 kg particle's position is r= (5.01-3.0 +4.0k) m, its velocity is v= (-1.01 + 3.0ĵ+ 1.0k) m/s, and the force on it is (13.01 +14.05) N. (Express your answers in vector form.) (a) What is the angular momentum (in kg-m²/s) of the particle about the origin? 7- kg-m²/s (b) What is the torque (in N-m) on the particle about the origin? N-m (c) What is the time rate of change of the particle's angular momentum about the origin at this instant (in kg-m²/s2)? di kg-m²/s² of

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At a particular instant, a 1.0 kg particle's position is r= (5.01-3.05 +4.0k) m, its velocity is v= (-1.01 +3.05 +1.0k) m/s, and the force on it is
F=(13.01 +14.05) N. (Express your answers in vector form.
(a) What is the angular momentum (in kg-m²/s) of the particle about the origin?
kg-m²/s
(b) What is the torque (in Nm) on the particle about the origin?
N-m
(c) What is the time rate of change of the particle's angular momentum about the origin at this instant (in kg. m²/s2)?
di
kg-m²/s²
dt
Transcribed Image Text:At a particular instant, a 1.0 kg particle's position is r= (5.01-3.05 +4.0k) m, its velocity is v= (-1.01 +3.05 +1.0k) m/s, and the force on it is F=(13.01 +14.05) N. (Express your answers in vector form. (a) What is the angular momentum (in kg-m²/s) of the particle about the origin? kg-m²/s (b) What is the torque (in Nm) on the particle about the origin? N-m (c) What is the time rate of change of the particle's angular momentum about the origin at this instant (in kg. m²/s2)? di kg-m²/s² dt
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