As shown below, a charged particle is moving through a region that has a uniform E-field (the red lines) and a uniform 2.5 T B-field. As a result of these two fields and the resulting forces (ignore gravity), the particle has a constant velocity of 126 m/s. A.) Determine the directions of FE & FB on the particle. Direction of FE Choose direction Direction of FB Choose direction ✓ B.) Determine the magnitude of the E-field and the direction of the B-field. Assume that the B-field is perpendicular to the velocity. E = Direction of B= [Choose direction

University Physics Volume 2
18th Edition
ISBN:9781938168161
Author:OpenStax
Publisher:OpenStax
Chapter11: Magnetic Forces And Fields
Section: Chapter Questions
Problem 22P: (a) A cosmic ray proton moving toward Earth at 5.00107 m/s experiences a magnetic force of 1.70l0l6...
icon
Related questions
Question
As shown below, a charged particle is moving through a region that has a uniform E-field (the red lines) and a uniform 2.5 T B-field. As a result of these two fields and the resulting forces (ignore gravity), the
particle has a constant velocity of 126 m/s.
i
A.) Determine the directions of FE & FB on the particle.
Direction of FE
Direction of FB =
B.) Determine the magnitude of the E-field and the direction of the B-field. Assume that the B-field is perpendicular to the
velocity.
E =
Direction of B Choose direction
Choose direction ✓
Choose direction
Transcribed Image Text:As shown below, a charged particle is moving through a region that has a uniform E-field (the red lines) and a uniform 2.5 T B-field. As a result of these two fields and the resulting forces (ignore gravity), the particle has a constant velocity of 126 m/s. i A.) Determine the directions of FE & FB on the particle. Direction of FE Direction of FB = B.) Determine the magnitude of the E-field and the direction of the B-field. Assume that the B-field is perpendicular to the velocity. E = Direction of B Choose direction Choose direction ✓ Choose direction
Expert Solution
Step 1

constant velocity (v) = 126 msmagnitude of electric field = Emagnitude of magnetic field (B)= 2.5 Tsign of charge = positive 

 

steps

Step by step

Solved in 3 steps

Blurred answer
Knowledge Booster
Magnetic field
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
University Physics Volume 2
University Physics Volume 2
Physics
ISBN:
9781938168161
Author:
OpenStax
Publisher:
OpenStax
College Physics
College Physics
Physics
ISBN:
9781938168000
Author:
Paul Peter Urone, Roger Hinrichs
Publisher:
OpenStax College