An electron is fired at a speed vo= 5.4 x 105 m/s and at an angle = -45° halfway between two parallel conducting plates that are D = 3.0 mm apart, as in the figure below. The voltage difference between the plates is AV = 95 V +- Path of the electron 0 Bo + AV 0 (a) Determine how close, d, the electron will get to the bottom plate. x Your response differs from the correct answer by more than 100%. mm (b) Determine the horizontal position where the electron will strike the top plate. (Report the distance from the origin along the x-axis.)

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Chapter19: Electric Potential And Electric Field
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Problem 15PE: The electric field strength between two parallel conducting plates separated by 4.00 cm is 7.50 104...
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An electron is fired at a speed v₁ = 5.4 x 106 m/s and at an angle = -45° halfway between two parallel conducting plates that are D = 3.0 mm apart, as in the figure below. The voltage difference between the plates is AV = 95 V.
D
+ + + +
Path of
the electron
0
00
+ + +
x
+
AV
(a) Determine how close, d, the electron will get to the bottom plate.
X
Your response differs from the correct answer by more than 100%. mm
(b) Determine the horizontal position where the electron will strike the top plate. (Report the distance from the origin along the x-axis.)
mm
Transcribed Image Text:An electron is fired at a speed v₁ = 5.4 x 106 m/s and at an angle = -45° halfway between two parallel conducting plates that are D = 3.0 mm apart, as in the figure below. The voltage difference between the plates is AV = 95 V. D + + + + Path of the electron 0 00 + + + x + AV (a) Determine how close, d, the electron will get to the bottom plate. X Your response differs from the correct answer by more than 100%. mm (b) Determine the horizontal position where the electron will strike the top plate. (Report the distance from the origin along the x-axis.) mm
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