An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass ma travels to the left with a speed of vĄ. Piece B with mass mg travels to the right with speed vg. Show the velocity of piece B in terms of ma mB and VA. Solution: Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so: PBf + PAf = 0 Substituting the expression for momentum results to mBv + MAV = 0 Deriving the expression for the velocity of piece B results to =(mA/m VA

Physics for Scientists and Engineers: Foundations and Connections
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ISBN:9781133939146
Author:Katz, Debora M.
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Chapter39: Relativity
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An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass ma travels to the left with
Piece B with mass mg travels to the right with speed vB. Show the velocity of piece B in terms of
a speed of
VA.
ma, mB and VA.
Solution:
Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so:
PBf +
PAf
= 0
Substituting the expression for momentum results to
mBV
mAV
= 0
Deriving the expression for the velocity of piece B results to
V
=(mA/m
VA
Transcribed Image Text:An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass ma travels to the left with Piece B with mass mg travels to the right with speed vB. Show the velocity of piece B in terms of a speed of VA. ma, mB and VA. Solution: Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so: PBf + PAf = 0 Substituting the expression for momentum results to mBV mAV = 0 Deriving the expression for the velocity of piece B results to V =(mA/m VA
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