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Air Cart on Pulley Experiment: a. Draw the free body force diagram of the dangling mass (m₂), when you are holding the system at rest. Be sure to label your coordinate system, to set up Fnet = ma in the next step. F hand Air cart m₁ Pulley Mass m₂ b. Draw the free body force diagram of the air cart (m₁), in this same configuration where you are holding the system at rest. Again, label coordinate axes. c. Write the three equations of Newton's Second Law for the two masses (x-component, y- component for the air cart and one equation for dangling mass) with proper signs for directions. Be clear about which equation corresponds to which object, and which direction.
Solve the equations for the tension force T in the string acting on the cart. What is the tension for the case m2 = 200 g?
Draw the free-body force diagram for the cart when it has been released and is accelerating.
Write the three equations of Newton’s Second Law for the two masses, now including their accelerations a1 and a2. Assuming the string length is constant, write also an equation relating the magnitudes of a1 and a2.
Solve these equations for the magnitudes of the accelerations, and for the magnitude of the tension force. What is the acceleration of the cart when m1 = 500g and m2 =200 g? What is the tension force for those mass values? Is the tension higher or lower than the static case of slide 5?