According to the following plot (velocity versus time) that refers to a cart with mass (m=0.75 kg) sliding on friction less surface horizontally. using the graph: The initial and final kinetic energy respectively. The initial time = 2 (sec) The final time = 4 KE=%mv2 Velocity (m/s) 5 4.5 4 3.5 3 2 1.5 1 0.5 0 (sec) 0 1 2 3 Time (s) 4 5 6 7

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter8: Conservation Of Energy
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Problem 57PQ
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According to the following plot (velocity versus time) that refers to a cart with mass (m=0.75 kg) sliding on friction less surface horizontally.
using the graph:
The initial and final kinetic energy respectively.
The initial time = 2 (sec)
The final time = 4 (sec)
KE=½mv²
Velocity (m/s)
5
4.5
4
3.5
3
2
2
1.5
1
0.5
0
0
1
2
3
Time (s)
4
5
6
7
Transcribed Image Text:According to the following plot (velocity versus time) that refers to a cart with mass (m=0.75 kg) sliding on friction less surface horizontally. using the graph: The initial and final kinetic energy respectively. The initial time = 2 (sec) The final time = 4 (sec) KE=½mv² Velocity (m/s) 5 4.5 4 3.5 3 2 2 1.5 1 0.5 0 0 1 2 3 Time (s) 4 5 6 7
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