a.department_name
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For SQL. I need to rewrite this as a left outer join.
select a.department_name,
b.first_name,
b.last_name
from l_departments a,
l_employees b
where a.dept_code = b.dept_code;
Step by step
Solved in 2 steps
- write SQL queries to create procedures for a database called Saleco. The database contains the following tables: customer, invoice, line, product, and vendor. A procedure called get_customer_invoices that takes a customer ID as input and returns a list of all invoices for that customer, along with the total amount due for each invoice. A procedure called get_vendor_products that takes a vendor ID as input and returns a list of all products sold by that vendor, along with the number of units sold and the total revenue generated for each product. A procedure called get_invoice_details that takes an invoice ID as input and returns a list of all products purchased on that invoice, along with the quantity purchased, the unit price, and the total price for each product.PLz help with the following Please implement the following using Oracle live/SQL Developer: 1- Create the DONORS table with the following columns: donor_id ( PRIMARY KEY), donor_name (Not Null), donor_age. Then Create DONATIONS table with the following columns: pledge_id (PRIMARY KEY), pledge_date, amount_pledged, amount_paid, Is_paid, donor_id that REFERENCES to DONORS table (donor_id). 2- Populate every relation with three rows. 3- Now, your supervisor has asked you to modify the donor_age column in the DONORS table. He wants the column to be configured to accept a value that must be >=20. Which statement should you issue to accomplish this task? 4- Create a Trigger to update Is_paid column to 1 when the amount_paid equal to amount_pledged.Create a Pl SQL package named EMP_PKG which will have the above three functions and procedures as follows: CALC_TAX - private CHECK_FNAME - Public AVG_SAL - Public
- SQL ( ORACLE SQL DEVELOPER ) : THIS IS FIRST , SECOND AND THIRD TABLE for the Task 1 to solve : create table author_45( auth_name char(50), gender char(1), age number(3), nationality char(50), PRIMARY KEY (auth_name) ); create table book_45( isbn number(10), title char(50), ver_no number(2), publisher char(50), PRIMARY KEY (isbn) ); create table writtenBy_45( isbn number(10), auth_name char(50), yr_published number(4), price number(3), no_copy number(4), PRIMARY KEY (isbn,auth_name), foreign key (isbn) references book_45, foreign key (auth_name) references author_45 ); insert into author_45 values ('Benoit','F',42,'French'); insert into author_ 45 values ('Antonini','M',33,'Italian'); insert into author_ 45 values ('McAven','F',31,'Australian'); insert into author_ 45 values ('Williams','M',90,'British'); insert into book_45 values (101,'atabases',1,'Possum'); insert into book_45 values (202,'SQL Primer',2,'Hall'); insert into book_45 values…Write the SQL statements for the following User table. User_id Name City Order_date Purchase_amount 101 Alex Paris 2012-10-05 150.5 102 James London 2012-10-05 270.3 103 Paul Paris 2012-10-05 120.8 104 Lawson Rome 2012-10-05 230.5 105 Kate Beijing 2012-10-05 30.2 Write a query to create a user table containing following columns. Whereas user_id as primary key. Write a query to insert multiple records into user table.THIS MODULE IS ABOUT SUBQUERIES, SO YOU MUST USE SUBQUERIES INSTEAD OF TABLE JOINS (a) From which two fields in which table can you calculate the enrollment of a section?(b) From which table can you get both course and section numbers?(c) Which field in table SECTION uniquely identifies a section, section id or section no?(d) Write a SQL statement to show sections and their enrollment.(e) Write a SQL statement to show sections with enrollment greater than five. Display both course andsection numbers
- 2) Write SQL query that returns the Name of ALL employees (based on EMP_LNAME and EMP_FNAME in EMPLOYEE table, call this EMP_NAME), Gender of ALL employees (based on EMP_TITLE in EMPLOYEE table, call this EMP_NAME), and Pilot ratings if any (PIL_RATINGS in PILOT table). Output: EMP_NAME EMP_GENDER Rhett VanDam M John Lange M Jeanine Duzak FMy SQL WORKBENCH **Please note that you may actually use as many tables as you need. You are not limited to use only twotables.Example:SELECT *FROM DEPARTMENTS;SELECT *FROM EMPLOYEES;Now join departments and employees tables.SELECT FIRST_NAME, DEPARTMENT_NAMEFROM EMPLOYEES, DEPARTMENTSWHERE EMPLOYEES.DEPARTMENT_ID = DEPARTMENTS.DEPARTMENT_ID;NOTE: If you omit the join condition, the result will be the Cartesian Product of the two tables. A CartesianProduct joins all rows of the first table with all rows of the second table.That is if the first table has n rows and the second table has m rows, the output will have n*m rows.The following query will produce a Cartesian Product:SELECT FIRST_NAME, DEPARTMENT_NAMEFROM EMPLOYEES, DEPARTMENTS;**When table names are long, qualifying column names might be very time consuming. Usually peopleprefer to use table aliases for this purpose.Example: List the name of all employees who work for 'Purchasing' departmentSELECT E.FIRST_NAME "EMPLOYEE…Write the SQL statements for the following User table. User_id Name City Order_date Purchase_amount 101 Alex Paris 2012-10-05 150.5 102 James London 2012-10-05 270.3 103 Paul Paris 2012-10-05 120.8 104 Lawson Rome 2012-10-05 230.5 105 Kate Beijing 2012-10-05 30.2 1. Write a query to create a user table containing following columns. Whereas user_id as primary key. 2. Write a query to insert multiple records into user table. 3. Write a query to add two columns, country and currency in user table. 4. Write a query to update user table, set city as shanghai for a user having user_id 105. 5. Write a query to remove all records from user table. 6. Write a query to drop a column purchase _amount from user table. 7. Write a query to display name of user in descending order whose order purchase amount is in between 200 to 270. 8. Write a query to display name of user who belong to either Paris, London or CS Beijing. 9. Write query to display name of an employee who belong to paris. 10. Write a…
- My SQL WORKBENCH **Please note that you may actually use as many tables as you need. You are not limited to use only twotables.Example:SELECT *FROM DEPARTMENTS;SELECT *FROM EMPLOYEES;Now join departments and employees tables.SELECT FIRST_NAME, DEPARTMENT_NAMEFROM EMPLOYEES, DEPARTMENTSWHERE EMPLOYEES.DEPARTMENT_ID = DEPARTMENTS.DEPARTMENT_ID;NOTE: If you omit the join condition, the result will be the Cartesian Product of the two tables. A CartesianProduct joins all rows of the first table with all rows of the second table.That is if the first table has n rows and the second table has m rows, the output will have n*m rows.The following query will produce a Cartesian Product:SELECT FIRST_NAME, DEPARTMENT_NAMEFROM EMPLOYEES, DEPARTMENTS;**When table names are long, qualifying column names might be very time consuming. Usually peopleprefer to use table aliases for this purpose.Example: List the name of all employees who work for 'Purchasing' departmentSELECT E.FIRST_NAME "EMPLOYEE…Question 5 You are working with a database table that contains customer data. The table includes columns about customer location such as city, state, country, and postal_code. You want to check for postal codes that are greater than 7 characters long. You write the SQL query below. Add a LENGTH function that will return any postal codes that are greater than 7 characters long. 1 2 3 4 5 SELECT * FROM customer WHERE RunReset What is the last name of the customer that appears in row 10 of your query result? 1 pointIn Sql Oracle Apex application, Using GROUPING SETS, write a query to show the following groupings:• department_id, manager_id, job_id• manager_id, job_id• department_id, manager_id