a) The acceleration of a 5.0 kg box is 2.5 ms?. when a horizontal force is applied across a surface having a coefficient of friction of 0.5, as shown in Figure 3. a = 2.5 ms-2 7 kg Hk = 0-5 Figure 3 Find the work done over a distance of 25 cm by ix. the horizontal force the frictional force, and Х. xi. the net force. xii. what is the change in kinetic energy of the box?
a) The acceleration of a 5.0 kg box is 2.5 ms?. when a horizontal force is applied across a surface having a coefficient of friction of 0.5, as shown in Figure 3. a = 2.5 ms-2 7 kg Hk = 0-5 Figure 3 Find the work done over a distance of 25 cm by ix. the horizontal force the frictional force, and Х. xi. the net force. xii. what is the change in kinetic energy of the box?
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Transcribed Image Text:a)
The acceleration of a 5.0 kg box is 2.5 ms?. when a horizontal force is applied across
a surface having a coefficient of friction of 0.5, as shown in Figure 3.
a = 2.5 ms-2
7 kg
Hk = 0.5
Figure 3
Find the work done over a distance of 25 cm by
ix.
the horizontal force
the frictional force, and
Х.
xi.
the net force.
xi.
what is the change in kinetic energy of the box?
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