A stationary conducting loop is placed in between the north pole and south pole of an artificial magnet. An increasing magnetic field is observed, increasing at the rate of 0.070 T/s. The conducting loop has a radius of 5 cm, and the vector area of the coil is perpendicular with the magnetic field vector. If a resistance of 80 was measured, calculate the induced current. *No backtracking. *Please be careful when answering, only your submission in BB will be considered as your final answer. *Focus on getting the correct answer, a separate time will be alloted for the uploading of the solutions. O 1.73 mA O 0.2159 mA O O A O 68.72 uA

University Physics Volume 2
18th Edition
ISBN:9781938168161
Author:OpenStax
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Chapter13: Electromagnetic Induction
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Problem 46P: Shown below is a conducting rod that slides along metal rails. The apparatus is in a uniform...
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A stationary conducting loop is placed in between the north pole and south pole of an artificial magnet. An increasing magnetic field is observed, increasing at
the rate of 0.070 T/s. The conducting loop has a radius of 5 cm, and the vector area of the coil is perpendicular with the magnetic field vector. If a resistance of
80 was measured, calculate the induced current.
*No backtracking.
*Please be careful when answering, only your submission in BB will be considered as your final answer.
*Focus on getting the correct answer, a separate time will be alloted for the uploading of the solutions.
O 1.73 mA
O 0.2159 mA
O O A
O 68.72 uA
Transcribed Image Text:A stationary conducting loop is placed in between the north pole and south pole of an artificial magnet. An increasing magnetic field is observed, increasing at the rate of 0.070 T/s. The conducting loop has a radius of 5 cm, and the vector area of the coil is perpendicular with the magnetic field vector. If a resistance of 80 was measured, calculate the induced current. *No backtracking. *Please be careful when answering, only your submission in BB will be considered as your final answer. *Focus on getting the correct answer, a separate time will be alloted for the uploading of the solutions. O 1.73 mA O 0.2159 mA O O A O 68.72 uA
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