A sex-influenced trait in humans is one that affects the length of the index finger. A "short" allele is dominant in males and recessive in females.Heterozygous males have an index finger that is significantly shorter than the ring finger. By comparison, the "long" allele is dominant in females andrecessive in males. The gene affecting index finger length is located on an autosome. A woman with short index fingers has children with a man who haslong index fingers. What are the following probabilities? (Assume that 50% of the offspring are male and 50% are female.)A. A daughter with long index fingersB. A daughter with short index fingersC. A son with sort index fingers

A break down of the probabilities for each scenario in detail: A. A daughter with long index…

Answered: A sex-influenced trait in humans is one…

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

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Similar questions

A sex-influenced trait in humans is one that affects the length of the index finger. A “short” allele is dominant in males and recessive in females. Heterozygous males have an index finger that is significantly shorter than the ring finger. The gene affecting index finger length is located on an autosome. A woman with short index fingers has children with a man who has normal index fingers. They produce five children in the following order: female, male, male, female, male. The oldest female offspring marries a man with normal fingers and then has one daughter. The youngest male among the five children marries a woman with short index fingers, and then they have two sons. Draw the pedigree for this family. Indicate the phenotypes of every individual (filled symbols for individuals with short index fingers and open symbols for individuals with normal index fingers).
A sex-influenced trait in humans affects the length of the index finger. A short allele is dominant in males and recessive in females.Heterozygous males have an index finger that is significantly shorterthan the ring finger. The gene affecting index finger length is locatedon an autosome. A woman with short index fingers has childrenwith a man who has normal index fingers. They produce five children in the following order: female, male, male, female, male. Theoldest female offspring has one daughter with a man who has normal fingers. The youngest male among the five children has childrenwith a woman with short index fingers; they have two sons. Drawthe pedigree for this family. Indicate the phenotypes of every individual (filled symbols for individuals with short index fingers andopen symbols for individuals with normal index fingers)
In man, muscular dystrophy is a condition in which the muscles waste away during early life and may result in a shorter life expectancy. It is due to a sex-linked, recessive gene. A certain couple has five children – three boys (ages 1yr, 3yrs, and 10yrs old) and two girls (ages 5yrs and 7yrs old). The oldest boy shows the symptoms of this disease. You are their family physician and they come to you for advice. What would you tell them about the chances of their other children developing the disease?
Huntington's disease is an inherited autosomal dominant disorder that can affect both men and women. Imagine a couple has had seven children, and later in life, the husband develops Huntington's disease. He is tested and it is discovered he is heterozygous for the disease allele, Hh. The wife is also genetically tested for the Huntington's disease allele, and her test results show she is unaffected, hh. What is the percent probability that the first child of this couple will have Huntington's disease? probability: % What is the percent probability that two of the seven children will have Huntington's disease? probability: %
X‑linked, recessive diseases, such as hemophilia, are extremely rare in the population. However, many women are carriers and show no sign of the disease. The pedigree illustrates the inheritance of an X‑linked, recessive disease. Determine whether the unknown individuals are affected by the disease, unaffected by the disease, or carriers of the X‑linked recessive allele. Unaffected individuals are not carriers of the X‑linked recessive allele.
In humans, blue eyes are inherited as a recessive autosomal trait and color blindness is an X-linked recessive trait. A woman with blue eyes and normal color vision (her father was colorblind) marries a man who has normal color vision. The man has brown eyes, but his mother had blue eyes. What is the probability that this couple will have a child with normal vision and blue eyes?
Geneticists are concerned about three different genetic conditions present within their family. Achondroplasia is an autosomal dominant genetic disorder that results in short-limbed dwarfism. (A = achondroplasia allele; a = average height allele). Red-Green Color blindness is an X-linked recessive genetic disorder (Xc = color blindness allele; XC = normal color vision allele). The 7-year-old son has an autosomal recessive form of deafness. (h = deafness allele; H = normal hearing allele.) All three family members were karyotyped, and additional genetic testing was performed to determine the chromosomal location of the genes being studied. The figures below show the karyotypes of the mother and father with respect to the chromosomes containing the three genes mentioned above. Question: The couple’s 7-year-old son has all three of these genetic conditions (achondroplasia, color blindness and deafness). Taking into consideration the genotypes of his parents, what is the complete…
Red-green color blindness is inherited as an X-linked recessive (Xc). If a color-blind man marries a woman who is heterozygous for normal vision, what would be the expected phenotypes of their children with reference to this character? In your answer, specify in your phenotype descriptions the gender of the children. (For example, don’t just say 75% of the children would be colorblind – you would instead say 100 % of the daughters would be colorblind and 50% of the sons would be colorblind. Note that this is not a correct answer; it is just to give you an idea of how to explain the correct phenotypes of the cross.)___
The gene for polydactyly (P) is autosomal and dominant to normal fingers (p). Hemophilia is sex-linked and recessive (X h ). A man and his wife both of whom are polydactylous and have normal red blood cells have a child who is non-polydactylous and with hemophilia. What are their genotypes?
Pompe disease is a glycogen storage disorder caused by a lack of a-glucosidase, the enzyme that converts glycogen to glucose in the muscles. Babies born with this disorder die by the age of two. Pompe disease is a genetic disorder caused by the presence of two recessive autosomal alleles. A man and a woman heterozygous for the condition have two female unaffected children. Determine the probability, expressed as a whole number percentage, of a third baby being born a male with Pompe disease. Your answer must include the use of a Punnett square as well as a legend indicating the allele symbols used.
In humans, the ABO blood type is under the control of autosomal multiple alleles. Color blindness is a recessive X-linked trait. If two parents who are both type A and have normal vision produce a son who is color-blind and is type O, what is the probability that their next child will be a female who has normal vision and is type O?
In humans, blue eyes are inherited as a recessive autosomal trait and color blindness is an X-linked recessive trait. A woman with blue eyes and normal color vision (her father was colorblind) marries a man who has normal color vision. The man has brown eyes, but his mother had blue eyes. What is the probability that this couple will have a son with brown eyes? What is the probability that this couple will have a color blind son with blue eyes?

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