A proton is moving in a circular orbit of radius 28.9 cm with a speed of 3.7*106m/s in a uniform magnetic field perpendicular to the velocity of the proton. Find the magnetic field in which the proton is moving. mp = 1.67×10-27 kg, charge of proton = 1.61×10-19C. Also calculate the time period of the proton.
A proton is moving in a circular orbit of radius 28.9 cm with a speed of 3.7*106m/s in a uniform magnetic field perpendicular to the velocity of the proton. Find the magnetic field in which the proton is moving. mp = 1.67×10-27 kg, charge of proton = 1.61×10-19C. Also calculate the time period of the proton.
Chapter11: Magnetic Forces And Fields
Section: Chapter Questions
Problem 31P: An alpha-particle ( m=6.641027kg , q=3.21019C ) travels in a circular path of radius 25 cm in a...
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A proton is moving in a circular orbit of radius 28.9 cm with a speed of 3.7*106m/s in a uniform magnetic field perpendicular to the velocity of the proton. Find the magnetic field in which the proton is moving. mp = 1.67×10-27 kg, charge of proton = 1.61×10-19C. Also calculate the time period of the proton.
Calculate the magnetic field and the time period to two decimal places. Submit the magnetic field as your answer. You are required to show your work in the file you submit.
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