A projectile is launched with a launch angle of 30° with respect to the horizontal direction and with an initial speed of 26 m/s. How do the vertical and horizontal components of the projectile's velocity vary with time?The initial velocity in the x-direction vx0 is related to the initial speed byvx0 = v0 cos 30°.The constant velocity in the x-direction means that the equation describing the time dependence of x for the particle, with x0 taken as 0, isx = x0 + vx0t = 0 + m/s t.The equation for the vertical coordinate, which is constantly accelerating downward at g = 9.8 m/s2, isy = y0 + vy0t − 12gt2 = m/s t+ m/s2 t2.

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Description: A projectile is launched with a launch angle of 30° with respect to the horizontal direction and with an initial speed of 26 m/s. How do the vertical and horizontal components of the projectile's velocity vary with time?The initial velocity in the x

The variation of vertical component with time is,

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College Physics

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A projectile is launched with a launch angle of 30° with respect to the horizontal direction and with an initial speed of 26 m/s.

How do the vertical and horizontal components of the projectile's velocity vary with time?

The initial velocity in the x-direction v_x0 is related to the initial speed by

v_x0 = v₀ cos 30°.

The constant velocity in the x-direction means that the equation describing the time dependence of x for the particle, with x₀ taken as 0, is

x = x₀ + v_x0t = 0 +

m/s

The equation for the vertical coordinate, which is constantly accelerating downward at g = 9.8 m/s², is

y = y₀ + v_y0t −

gt² =

m/s

m/s²

t².

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