A potential difference of 2.95 V is applied across points a and bin the figure. R¡ is equal to 6.25 2, R, is equal to 14.52, andR3 is equal to 8.75 2. Find the current through each of the resistors, and the total current otal that the three resistors draw fromthe power source.DA circuit segment beginning with a single wire at point A that then splitsinto three parallel branches. Each of the three branches has a single resistor,and the resistors are labeled R subscript 1, R subscript 2, and R subscript 3.The parallel branches recombine after the resistors, and the circuit segmentterminates as a single wire at point b.AI2 =I3 =IstalA

A potential difference of 2.95 V is applied across points a and b in the figure. R, is equal to 6.25 2, R, is equal to 14.5Q, and R3 is equal to 8.752. Find the current through each of the resistors, and the total current Iotal that the three resistors draw from the power source.

A potential difference of 2.95 V is applied across points a and b in the figure. R, is equal to 6.25 2, R, is equal to 14.5Q, and R3 is equal to 8.752. Find the current through each of the resistors, and the total current Iotal that the three resistors draw from the power source.

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter9: Current And Resistance

Section: Chapter Questions

Problem 55P: A 20.00-V battery is used to supply current to a 10-k resistor. Assume the voltage drop across any...

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Question

A potential difference of 2.95 V is applied across points a and bin the figure. R¡ is equal to 6.25 2, R, is equal to 14.52, and
R3 is equal to 8.75 2. Find the current through each of the resistors, and the total current otal that the three resistors draw from
the power source.
DA circuit segment beginning with a single wire at point A that then splits
into three parallel branches. Each of the three branches has a single resistor,
and the resistors are labeled R subscript 1, R subscript 2, and R subscript 3.
The parallel branches recombine after the resistors, and the circuit segment
terminates as a single wire at point b.
A
I2 =
I3 =
Istal
A

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