A point mass moving on a vertical line has an acceleration given by the equation a = 10t – 3. At t = 0, the displacement is found to be s = - 5m. And after at t = 7s, the displacement is s = 12m. Derive the equation of its motion. Use the boundary conditions to solve for the constants of integration. C2 eqn.

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Author:William Moebs, Samuel J. Ling, Jeff Sanny
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Chapter3: Motion Along A Straight Line
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A point mass moving on a vertical line has an
acceleration given by the equation a = 10t – 3.
At t = 0, the displacement is found to be s =
- 5m. And after at t = 7s, the displacement is
s = 12m. Derive the equation of its motion.
Use the boundary conditions to solve for the
constants of integration.
C2
eqn.
Transcribed Image Text:A point mass moving on a vertical line has an acceleration given by the equation a = 10t – 3. At t = 0, the displacement is found to be s = - 5m. And after at t = 7s, the displacement is s = 12m. Derive the equation of its motion. Use the boundary conditions to solve for the constants of integration. C2 eqn.
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