A movie stuntman (mass 80.0 kg) stands on a window ledge 5.0 m above the floor. Grabbing a rope attached to a chandelier, he swings down to grapple with the movie's villain (mass 70.0 kg), who is standing directly under the chandelier. Find the velocity of the stuntman just before hitting the villain. ( Assume that the stuntman's center of mass moves downward 5.0 m. He releases the rope just as he reaches the villain.)

Classical Dynamics of Particles and Systems
5th Edition
ISBN:9780534408961
Author:Stephen T. Thornton, Jerry B. Marion
Publisher:Stephen T. Thornton, Jerry B. Marion
Chapter9: Dynamics Of A System Of Particles
Section: Chapter Questions
Problem 9.60P
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5.0 m
m = 80.0 kg
m = 70.0 kg
Transcribed Image Text:5.0 m m = 80.0 kg m = 70.0 kg
A movie stuntman (mass 80.0 kg) stands on a window ledge 5.0 m above the floor. Grabbing a rope
attached to a chandelier, he swings down to grapple with the movie's villain (mass 70.0 kg), who is
standing directly under the chandelier. Find the velocity of the stuntman just before hitting the villain. (
Assume that the stuntman's center of mass moves downward 5.0 m. He releases the rope just as he
reaches the villain.)
Transcribed Image Text:A movie stuntman (mass 80.0 kg) stands on a window ledge 5.0 m above the floor. Grabbing a rope attached to a chandelier, he swings down to grapple with the movie's villain (mass 70.0 kg), who is standing directly under the chandelier. Find the velocity of the stuntman just before hitting the villain. ( Assume that the stuntman's center of mass moves downward 5.0 m. He releases the rope just as he reaches the villain.)
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