A material with an Ultimate Tensile Strength (UTS) of 400 Mpa is loaded cyclically about mean stress of 80 MPa. If the stress range that will cause fatigue fracture in 100 000 cycles under zero mean stress is (+,- )60 MPa, what stress range (in MPa) about the mean of 70 MPa will give the same life

A material with an Ultimate Tensile Strength (UTS) of 400 Mpa is loaded cyclically about mean stress of 80 MPa. If the stress range that will cause fatigue fracture in 100 000 cycles under zero mean stress is (+,- )60 MPa, what stress range (in MPa) about the mean of 70 MPa will give the same life

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter8: Applications Of Plane Stress (pressure Vessels, Beams, And Combined Loadings)

Section: Chapter Questions

Problem 8.2.8P: A spherical steel pressure vessel (diameter 500 mm, thickness 10 mm) is coated with brittle lacquer...

See similar textbooks

Related questions

Q: Determine the endurance limit of the material with a force 30 lbs led to a facture after 105…

Q: A material with an Ultimate Tensile Strength (UTS) of 350 Mpa is loaded cyclically about mean stress…

A: The relationship between Goodman is an equation used to measure the interplay of mean and…

Q: In a structure subjected to fatigue loading, the minimum and maximum stresses developed in a cycle…

A: Given:minimum stress, σmin=200 MPamaximum stress, σmax=400 MPa

Q: Q/Figure i shows the stress and strain curve of a ... metal sample of standard length (250 mm) and…

A: Given: The stress-strain curve for the given sample is shown below:

Q: Question 6 What is the calculated fracture toughness, K, for the perspex specimen in MPa root m?…

A: Given data: P=250 NW=13.3 mmB=5.45 mmfa/W=0.78 Need to determine the span length.

Q: Consider a steel plate with a through-thickness edge crack like the one shown in Fig. 6.21f. The…

Q: Estimate the fatigue strength of a rotating-beam made of AISI 1035 CR steel corresponding to a life…

Q: length (lo)-2.0 in.): Load (lb)) 0.0 Al (in) 0.0 3000 0.00167 from a standard 0.505-in. 6000 7500…

Q: Steel subject to tensile stress of 1030 MPa, it has K1c of 54.8 MPa(m) – a handbook value If it has…

Q: A 200mm long rod with a diameter of 50mm is loaded with a 4kN weight. The rod final length 201.314mm…

A: Given data :- L = 200 mm D = 50 mm Weight = 4KN Final length = 201.314 mm Final diameter = 42 mm…

Q: A tie rod made of quenched and tempered 4340 steel is used as a critical linkage in an industrial…

A: Given data as per question for the given 4340 steel Tensile stress =550 MpaCompressive stress…

Q: To use Hooke's law and the definitions of stress and strain to calculate unknown values for linear…

A: Part A: Given data, Writing the formula for change in length due to axial load: -

Q: A steel specimen 12mm diameter has gauge length 50mm. the steel specimen had tested via tensile…

A: You have posted multiple questions on single window. As per the guidelines I am able to answer first…

Q: A circular bar - shown below, made of AISI 1040 OQT 1300 steel (SU = 600 MPa), is loaded with an…

A: Given: Steel of a particular grade. Ultimate stress, Su = 600 MPa D = 36mm d = 30 mm r = 2.4mm No of…

Q: Can the maximum normal stress theory or Mohr’s failure criterion be used in practice to predict the…

Q: ). A ceramic bar of diameter do = 5 mm has a fracture toughness Kic = 2.35 MNm-3/2. If this bar is…

Q: Fatigue fracture surface has 3 zones such as (1) initiation, (2) crack propagation and (3) sudden…

A: Fatigue is a type of failure which is independent of time that can occur in a material without any…

Q: Sketch the stress-strain curves for two ductile metals (A and B) that fracture at the same total…

A: Since it is given that the total strain at the time of fracture of both the bodies A and B is the…

Q: A copper rod [E= 110 GPa] originally 599 mm long is pulled in tension with a normal stress of 278…

Q: A cold drawn 1144 Stressproof steel specimen with a diameter of 0.874 in. and a 1.0 in. gage length…

A: Given: The diameter of specimen, d = 0.874 in The length of the gage, L = 1.0 in

Q: A very wide plate with a 2" long center crack is heated in order to be brazed to its end supports.…

Q: The is a graphical representation of fatigue strength on the Y-axis and the number of stress cycles…

Q: Example 5.2 A cylindrical test sample of diameter 12.8 mm is tested in tension up to fracture and…

Q: Failure of Materials Due to Creep and Fatigue.

A: Environmental conditions, such as corrosion, have an impact on fatigue strength. The fatigue…

Q: A tensile stress is to be applied along the axis of a cylindrical brass rod with diameter of 200 mm.…

A: since you haven't mentioned the value of poison ration and elastic modulus that's why the reference…

Q: A nylon material has a fracture toughness K1c = 2.1 MPa.m1/2 It follows a Paris Law for fatigue with…

A: Given : K = 2.1 Mpa.m1/2 C = 4 x 10-8 n = 3.2 N = 63387 To find a

Q: A large flat plate is subjected to constant-amplitude uniaxial cyclic tensile and compressive…

A: Given Dataa=1mmKk=35MPa m1/2m=3.5A=5×10-12 MPaY=1.3σmax=120MPaσmin=35MPa

Q: During a high cycle fatigue test, a metallic specimen is subjected to cyclic loading with a mean…

A: Given:σmin=-70 MPaσmean=+140 MPa

Q: A tie rod made of quenched and tempered 4340 steel is used as a critical linkage in an industrial…

A: Given :- Type of steel : 4340 steel Tensile strength : 550 Mpa a : 3.5 mm

Q: modulus, E 200 700 yield strength, Øy (MPa) 900 TH-SAI-2.55n titanium alloy 600 4340 steel tensile…

A: for 4340 steel tensile stress σT=550 Mpa compressive stress σC= -550 MpaKIC = 55 Mpa m crack…

Q: A certain force F is applied at D. OABC bar is made of a brittle material with 210 MPa ultimate…

Q: Tensile and fully reversed loading fatigue tests were conducted for a certain steel alloy and…

A: σy = 1200 MPa (tensile) σe = 550 MPa (comp) static stress = 600 MPa σtensile = 350 MPa σcomp = 350…

Q: A steel of rotating-beam test specimen has an ultimate strength of 1100Mpa. Estimate the fatigue…

Q: The fatigue (endurance) limit of a 1045 (plain carbon) stcel is about 300 MN/m² when the mean stress…

A: Given data Endurance limit (Se) = 300 MN/m^2 Tensile strength (Sut) = 750 MPa Mean stress ( sigma m)…

Q: 2.33. AISI 403 stainless steel has a fracture toughness Kje =77 MPa m and a uni- axial yield stress…

Q: A titanium tube with an outside diameter of 25 mm and inside diameter of 20 mm and a length of 200…

Q: A steel specimen 12mm diameter has gauge length 50mm. the steel specimen had tested via tensile…

Q: A fatigue test was conducted in which the mean stress was 550 MPa and the stress amplitude was 320…

Q: Question 1 A circular bar - shown below, made of AISI 1040 OQT 1300 steel (Su = 600 MPa), is loaded…

A: Given data: Calculate the required ratios.

Q: 1)Consider a material with K, = 50 MPa.m/2. Assume that the geometry factor Y is equal to 1. In the…

A: The critical stress for cracked specimen is to be investigated. Following formula is used for the…

Q: The flexural strength of a composite material reinforced with glass fibers is 45,000 psi, and the…

A: Given data: Flexural strength, σ = 45000 psi. Flexural modulus, E = 18×106 The length of the…

Q: Tensile and fully reversed loading fatigue tests were conducted for a certain steel alloy and…

Q: Suppose that a wing component on an air- craft is fabricated from an aluminum alloy that has a plane…

A: Given:Fracture toughness, ktc=40 MPamStress, σ=365 MPaCrack length, a=2.5 mmCritical crack length,…

Q: Answer the following questions about the Ductile-to-Brittle Transition Temperature (DBTT). Explain…

A: Ductile to brittle transition testing is done on various materials to view the behavior of metals…

Concept explainers

Thermal Properties of Materials

In mechanical engineering, the thermal property is represented as the physical quantity that is relevant to the application of heat. The thermal properties are evaluated by variations in any specific material due to low heat or high heat. The quantities that influence the thermal property of the materials are mass, density, temperature, and many others.

Question

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Types of Properties of Engineering Materials

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions

A wine of length L = 4 ft and diameter d = 0.125 in. is stretched by tensile forces P = 600 lb. The wire is made of a copper alloy having a stress-strain relationship that may be described mathematically by =18,0001+30000.03(=ksi) in which is nondimensional and has units of kips per square inch (ksi). (a) Construct a stress-strain diagram for the material. (bj Determine the elongation, of the wire due to the Forces P. (c) IF the forces are removed, what is the permanent set of the bar? (d) If the forces are applied again, what is the proportional limit?
The rails of a railroad track are welded together at their ends (to form continuous rails and thus eliminate the clacking sound of the wheels) when the temperature is 60°F. What compressive stress ?? =6.5×10-6 /? is produced in the rails when they are heated by the sun to 120"F if the coefficient of thermal expansion a = the modulus of elasticity E = 30 × 106 psi?
Determine the strain energy per unit volume (units of psi) and the strain energy per unit weight (units of in ) that can be stored in each or the materials listed in the accompanying table, assuming that the material is stressed to the proportional limit. DATA FOR PROBLEM 2.7-5 Material Weight Density (lb/in3) Modulus of Elasticity (ksi) Proportional Limit (psi) Mild sleel 0.284 30,000 36,000 Tool steel 0.284 30,000 75,000 Aluminum 0.0984 10,500 60,000 Rubber (soft) 0.0405 0.300 300
A spherical steel pressure vessel (diameter 500 mm, thickness 10 mm) is coated with brittle lacquer that cracks when the strain reaches 150 X 10~ (see figure). (a) What internal pressure p will cause the lacquer to develop cracks? (Assume E = 205 GPa and v = 0.30.) (b) If the strain is measured at 125 x 10-6, what is the internal pressure at that point?
A material with an Ultimate Tensile Strength (UTS) of 350 Mpa is loaded cyclically about mean stress of 70 MPa. If the stress range that will cause fatigue fracture in 100 000 cycles under zero mean stress is (+,- )60 MPa, what stress range (in MPa) about the mean of 70 MPa will give the same life
Uniaxial yield stress of a material is 260 MPa Determine shear yield stress using Von Mises criteria.
2. In the stress-strain curve for steel shown below, identify following stresses in ksi and write their values in the space below: 2.1. Yield Point: ksi 2.2. Ultimate Tensile Strength: ksi 60- 400 350 50 300 E 40 250 30 200 150 20 100- 10 50 0. Strain, in/in or m/m J stv A Aa Stress, MPa Stress, ksi
Example: Convert the change in length data in Table 3-2 to engineering stress and strain and plot a stress-strain curve Homework- help Table 3-2 The results of a tensile test of a 0.505 in. diameter aluminum alloy test bar, initial length (1o) = 2 in. Calculated LTO Load (Ib) Change in Length (in.) Stress (psi) Strain (in./in.) 0.000 1000 0.001 0.0005 4,993 14,978 24,963 34,948 37,445 39,442 39,941 39,691 37,944 3000 0.003 0.0015 5000 0.005 0.0025 7000 0.007 0.0035 7500 0.030 0.0150 7900 0.080 0.0400 8000 (maximum load) 0.120 0.0600 7950 0.160 0.0800 7600 (fracture) 0.205 0.1025
1. A part made of Aluminum 6061-T6 has a yield strength = 400 MPa. For each stress state below, draw all 3 Mohr's circles, find the principal stresses, and calculate the safety factor against yield using both the distortion-energy (von Mises) and maximum shear stress (Tresca) criterions. (If relevant) A clearly labeled diagram (or diagrams) clearly pertaining to your analysis with a coordinate system and relevant labels. Final answer with appropriate units and significant figures. You can use the fprintf() command in MATLAB to format numerical results A 2-3 sentence reflection on your answer. Does it make sense? Why or why not? What are some implications?
A fatigue test was conducted in which the mean stress was 70 MPa (10150 psi), and the stress amplitude was 230 MPa (33360 psi). (a) Compute the maximum stress level. i (b) Compute the minimum stress level. i (c) Compute the stress ratio. i MPa i MPa (d) Compute the magnitude of the stress range. MPa
1. For the stress-strain curve shown below, please estimate the properties indicated. (a) Fracture Strain Please do your work on a separate sheet of paper, and put your answers in the boxes on the right. Be sure to include the proper symbol and units. Stress Strain 70 60 50 Stress (ksi) 240 30 20 10 70 0 0.000 60 50 Stress (ksi) 40 20 10 KULL 0 0.000 0.010 0.050 0.100 Strain (in/in) Stress Strain 0.020 0.030 Strain (in/in) 0.040 0.150 0.050 (b) Ultimate Tensile Stress (c) Fracture Stress (d) Proportional Limit (e) Elastic Modulus (1) Yield Stress (g) Tensile Toughness (Modulus of Toughness) (h) Modulus of Resilience
*O llAsiacell Strength of m. -> 02: A steel specimen 12mm diameter has gauge length 50mm. the steel specimen had tested via tensile test under maximum load 66KN with elongation 7.5mm, and the yield load of this specimen is 15KN with elongation 2.4mm. Calculate: 1- The engineering ultimate stress (ultimate tensile strength), and engineering strain at this point. 2- The engineering stress and strain at yield point. 3- The modulus of elasticity, and the modulus of resilience. 4- The final or fracture strain of a steel specimen, if you know that the final length of specimen after testing is 58.5mm. 5- The true stress and strain for ultimate point. Q3: The yoke-and-rod connection is subjected to a tensile force of 15 kN. Determine the average normal stress in each rod and the average shear stress in the pin A between the members. Finally, find the shear strain in pin A. Take G teef 75GPA 40 mm 15 kN, 30 mm 30 mn 15 kN 04: In figure as shown below, assume that a 35mm diameter rivet joint the…