A force of 5000N is applied outwardly to each end of a 5.0-m long rod with a radius of 34.0 cm and a      Young’s modulus of 125 × 10^8 N/m2. The elongation of the rod is: Choices: 1.42mm 0.14mm 0.0040mm 0.55mm 0.0020mm   Show complete solution and free body diagram

Q: A 1.05-m-long rod of negligible weight is supported at its ends by wires A and B of equal length…

A: Given data: Length of the rod, L=1.05 m Area of wire A, aA=2.37 mm2 Area of wire B, aB=3.85 mm2…

Q: end of a steel rod of radius R = 10mm and length L= 80 cm is held in a vise. A force of magnitude F…

A: Youngs modulus = mgL/πr²ΔL

Q: A rod with a radius of 0.005 m and length of 2 m stretches 0.002 m when subjected to a tension force…

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Q: A 463-N object is hung from the end of a wire of cross-sectional area 0.03 cm-. The wire stretches…

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Q: One end of a steel rod of radius R = 10mm and length L = 90 cm is held in a vise. A force of…

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Q: A nylon rope used by mountaineers elongates 1.8 m under the weight of a 68-kg climber. If the rope…

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Q: For safety in climbing, a mountaineer uses a nylon rope that is 65 m long and 1.4 cm in diameter.…

A: Given: Length of nylon rope L= 65 m long Diameter of rope , d = 1.4 cm Mass of climber, m= 85 kg…

Q: A man with a mass of 71.6 kg stands on one foot. His femur has a cross-sectional arca of 8.00 cm2…

A: Given : Mass of man = 71.6 kg Cross-sectional area of femur = 8.00 cm2= 8.00*10-4 m2 Uncompressed…

Q: YOUNGS MODULUS FOR A 4m LONG METAL ROD WITH A 0.50cm2 CROSS SECTIONAL AREA THAT STRETCHES 0.20cm UN

A: GivenLength of rod, L=4 mArea of rod, A=0.5 cm2=0.5×10-4 m2Strech length, ∆L=0.2 cm=0.2×10-2…

Q: A steel wire of length 2.08 m with circular cross section must stretch no more than 0.300 cm when a…

A: Write the formula for Young’s modulus.

Q: Consider a rod, when applied with a certain force, reverts to its original form. With stress given…

A: Given data: Stress (σ) = 3.0 GPa Strain (ε) = 0.230 Required: Young’s modulus (Y)

Q: What could be the change in length of the wire with a cross sectional area of  0.000025 m2 with…

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Q: An object with a mass equal to 300 kg is hung on a wire of length 5.00 m and cross-sectional area of…

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Q: A rod with a radius of 0.005 m and length of 2 m stretches 0.002 m when subjected to a tension force…

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Q: What is the tension force in the wire shown below if it stretches O.35 cm when tightened if young's…

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Q: What is the tension force in the wire shown below if it stretches 0.35 cm when tightened if young's…

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Q: What is the tension force in the wire shown below if it stretches 0.35 cm when tightened if young's…

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Q: Humans can bite with a force of approximately 793 N. If a human tooth has the Young's modulus of…

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Q: A 1.05-m-long rod of negligible weight is supported at its ends by wires A and B of equal length…

A: Solution:a.Stress in the wire will be given as:   Stress= Fa  Thus we get:  F1a1 = F2a2…

Q: Q20 A plastic dowel has a Young's Modulus of 1.50 ✕ 1010 N/m2. Assume the dowel will break if more…

A: Given  Young's modulus Y=1.5×1010 N/m2 maximum stress Emax=1.5×108 N/m2 Diameter d=2.30cm Radius…

Q: A 542-N object is hung from the end of a wire of cross-sectional area 0.07 cm2.  The wire stretches…

A: Applied force, F = 542 N Area of cross section, A = 0.07 cm² = 0.07 × 10-4 m² Original length, L =…

Q: a metal rod with length 2 m and cross sectional area of 0.002 m2 has a youngs modulus of 20x10^10Pa.…

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Q: If you bend a rod down, it compresses the lower side of the rod and stretches the top, resulting in…

A: It is given that,

Q: BIO Biceps Muscle. A relaxed biceps muscle requires a force of 25.0 N for an elongation of 3.0 cm;…

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Q: A stainless-steel orthodontic wire is applied to a tooth. The wire has an unstretched length of 3.62…

A: Given Data   The length of the wire is L0 = 3.62 cm. The radius of the wire is r = 0.13 mm. The…

Q: A weight of (50kg) affects the lower end of a steel rod of length (80cm) and diameter (0.60cm). What…

A: Given: The mass of the weight is 50 kg. The length of the rod is 80 cm. The diameter of the rod is…

Q: The unit of which physical quantity is not pascal? A) Moment of inertia B) Pressure C) Stress D)…

A: Unit of moment of inertia is kg m2.  Unit of pressure is Pascal.  Unit of stress is newton per sq.…

Q: "One end of a steel rod of radius R = 10mm and length L = 80 cm is held in a vise. A force of…

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Q: Which of the following is a dimensionless quantity? Select one: a. Shear stress b. Poison's ratio c.…

A: As we dimensionless quantity are those which have no dimensions i.e   M0 L0 T0

Q: A man with a mass of 68.3 kg stands on one foot. His femur has a cross-sectional area of 8.00 cm2…

A: GivenM= 68.3 kgA =8.00 cm2 =8.00 ×10-4 m2uncompressed length (L) = 50.4 cm = 50.4 × 10-2 mYoung's…

Q: A 242-N object is hung from the end of a wire of cross-sectional area 0.01 cm2.  The wire stretches…

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Q: A 1.05-m-long rod of negligible weight is supported at its ends by wires A and B of equal length…

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Q: Normal forces of magnitude 3.0 x 10° N are applied uniformly to a spherical surface enclosing a…

A: As per our guidelines we are supposed to answer?️ only one question. Kindly repost other questions…

Q: What is the tension force in the wire shown below if it stretches 0.35 cm when tightened if young's…

A: Since Young's modulus is given by, Y = Stress/Strain Stress = Tension Force/Area = T/A Strain =…

Q: Four cylindrical rods are stretched. The force magnitudes, the cross sectional area, the initial…

A: Given, We know the expression for young modulus is  Y=FA(L0∆L)

Q: A cylindrical aluminum rod, with an initial length of 0.8880 m and radius 849.7 µm, is clamped in…

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Q: If you bend a rod down, it compresses the lower side of the rod and stretches the top, resulting in…

A: The given relation for the restoring force is

Q: Young's modulus of nylon is 3.7 × 109 N/m2. A force of 6.0 × 105 N is applied to a 1.5-m length of…

A: Given data: The Young's modulus of nylon is E=3.7×109 N/m2. The force applied is F=6.0×105 N. The…

Q: Solve the problem correctly. Show a detailed and neat solution. A 200-kg load is hung on a wire of…

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Q: A man with a mass of 68.3 kg stands on one foot. His femur has a cross-sectional area of 8.00 cm2…

A: Given:The mass of man, m = 68.3 kgThe area of femur, A = 8 cm2 = 8×10-4 m2The length which is…

Q: Fire fighter had an accident leads to injury in his thigh, caused fracture in his femur (consider it…

A: Change in length of bone, ∆L=0.08 mm ⇒0.08×10-3 Applied force, F=500 N Cross sectional area,…

Q: The gusset plate is subjected to the forces of three members. Determine the tension force in member…

A: Solution: Given that F = 8 kN TC = ? TA = 9 kN

Q: An object with a mass equal to 300 kg is hung on a wire of length 5.00 m and cross-sectional area of…

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Q: A material rod that is 4.00 m long and 0.50 cm2 in cross- section area is found to stretch 0.20 cm…

A: The Young's Modulus, Y=Fl0A∆l

Q: A road with a radius of 0.005m and length of 2m stretched to a tension force of 10000N young's…

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Mechanical Properties of Solids

There are three types of matter- solid, liquid and gas. Out of them, solids have a rigid shaped and size. The intermolecular forces of attractions in solids are greatest. Mechanical properties are the physical properties of a material which it shows, when it is provided with certain amount of force or load. These properties are to be kept in mind for various purposes. When a force is applied to an object, the object may or may not get deformed depending upon its elastic property. But every time the object develops a restoring force against the force applied. This is commonly known as stress. If the object changes its dimensions due to the force applied it develops strain ( which is the ratio of change in dimension to the original dimension).