A bicycle racer sprints near the end of a race to clinch a victory. The racer has an initial velocity of 10.65 m/s and accelerates at the rate of 0.65 m/s2 for 6.75 s to accomplish this. What is his final velocity, in meters per second, after this period of acceleration? The racer continues at this velocity to the finish line. If he was 325 m from the finish line when he started to accelerate, how much less time did it take him to finish then if had had not accelerated? One other racer was 9.5 m ahead when the winner started to accelerate, but was too tired to speed up and traveled at 12.1 m/s until the finish line. If the winner continues to cycle at the same speed after crossing the finish line (to celebrate his victory), how far ahead of the loser will the winner be, in meters, when the loser finishes?
A bicycle racer sprints near the end of a race to clinch a victory. The racer has an initial velocity of 10.65 m/s and accelerates at the rate of 0.65 m/s2 for 6.75 s to accomplish this.
What is his final velocity, in meters per second, after this period of acceleration?
The racer continues at this velocity to the finish line. If he was 325 m from the finish line when he started to accelerate, how much less time did it take him to finish then if had had not accelerated?
One other racer was 9.5 m ahead when the winner started to accelerate, but was too tired to speed up and traveled at 12.1 m/s until the finish line. If the winner continues to cycle at the same speed after crossing the finish line (to celebrate his victory), how far ahead of the loser will the winner be, in meters, when the loser finishes?
Let the initial velocity of the winner be u1, the final velocity of the winner after the period of acceleration be v1, the acceleration of winner be a, and the period of acceleration be t1.
The value of v1 is calculated by using the following equation of motion.
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