A barbell spins around a pivot at its center at A. The barbell consists of two small balls, each with mass 500 grams (0.5 kg), at the ends of a very low mass rod of length d = 30 cm (0.3 m; the radius of rotation is 0.15 m). The barbell spins clockwise with angular speed 100 radians/s. m m II: Treat the object as one barbell (h) Calculate the moment of inertia I of the barbell. I = kg Â. m2 (j) Use the moment of inertia I and the angular speed || = 100 rad/s to calculate the rotational angular momentum of the barbell: ka Ô, m2/s

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter10: Rotational Motion
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Problem 11P: A disk 8.00 cm in radius rotates at a constant rate of 1200 rev/min about its central axis....
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A barbell spins around a pivot at its center at A. The barbell consists of two small balls, each with mass 500 grams (0.5 kg), at the
ends of a very low mass rod of length d = 30 cm (0.3 m; the radius of rotation is 0.15 m). The barbell spins clockwise with
angular speed 100 radians/s.
m
m
II: Treat the object as one barbell
(h) Calculate the moment of inertia I of the barbell.
I =
kg Â. m2
(j) Use the moment of inertia I and the angular speed ||
= 100 rad/s to calculate the rotational angular momentum of the
barbell:
|Trotl = I || =
kg Â. m²/s
Transcribed Image Text:A barbell spins around a pivot at its center at A. The barbell consists of two small balls, each with mass 500 grams (0.5 kg), at the ends of a very low mass rod of length d = 30 cm (0.3 m; the radius of rotation is 0.15 m). The barbell spins clockwise with angular speed 100 radians/s. m m II: Treat the object as one barbell (h) Calculate the moment of inertia I of the barbell. I = kg Â. m2 (j) Use the moment of inertia I and the angular speed || = 100 rad/s to calculate the rotational angular momentum of the barbell: |Trotl = I || = kg Â. m²/s
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