A ball of mass m = 1.04kg has its position as a function of time given by F(t) = (5m + 1.97m cos (1.05 t)) + (6.17t) j^+ (1.6t²) k (The input below will accept answers with no more than 1% variation from the correct value.) What is the particle's angular momentum around the origin at t = 1.48s? L (1.48s) = kg¹i4 kg™j+ kg k
A ball of mass m = 1.04kg has its position as a function of time given by F(t) = (5m + 1.97m cos (1.05 t)) + (6.17t) j^+ (1.6t²) k (The input below will accept answers with no more than 1% variation from the correct value.) What is the particle's angular momentum around the origin at t = 1.48s? L (1.48s) = kg¹i4 kg™j+ kg k
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Transcribed Image Text:A ball of mass m = 1.04kg has its position as a function of time given by
r(t) = (5m + 1.97m cos (1.05 t)) + (6.17t) + (1.6²) k
(The input below will accept answers with no more than 1% variation from the correct value.)
What is the particle's angular momentum around the origin at t = 1.48s?
L(1.48s) =
kg ™²i+
kg² j4
a kg k
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