(a) A small light fixture on the bottom of a swimming pool is 0.92 m below the surface. The light emerging from the still water forms a circle on the water surface. What is the diameter of this circle? (Give your answer, in m, to at least tw decimal places.) Xm (b) What If? If a 1.63 cm thick layer of oil (noil = 1.35) is spread uniformly over the surface of the water, what is the diameter of the circle of light emerging from the swimming pool? (Give your answer, in m, to at least two decimal places.) x m

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter27: Wave Optics
Section: Chapter Questions
Problem 38P
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(a) A small light fixture on the bottom of a swimming pool is 0.92 m below the surface. The light emerging from the still
water forms a circle on the water surface. What is the diameter of this circle? (Give your answer, in m, to at least two
decimal places.)
Xm
(b) What If? If a 1.63 cm thick layer of oil (noil = 1.35) is spread uniformly over the surface of the water, what is the
diameter of the circle of light emerging from the swimming pool? (Give your answer, in m, to at least two decimal
places.)
X m
Transcribed Image Text:(a) A small light fixture on the bottom of a swimming pool is 0.92 m below the surface. The light emerging from the still water forms a circle on the water surface. What is the diameter of this circle? (Give your answer, in m, to at least two decimal places.) Xm (b) What If? If a 1.63 cm thick layer of oil (noil = 1.35) is spread uniformly over the surface of the water, what is the diameter of the circle of light emerging from the swimming pool? (Give your answer, in m, to at least two decimal places.) X m
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