A 50 kg crate sits on a flat horizoral floor. A rope is attached and pulled horizontally to the right. Let T, N and F be the magnitude of the tension force (T), the normal force (N) and the friction force (F) respectively. Take acceleration due to gravity to be 10 ms-². a) b) c) Copy the diagram and show on it the direction of T, N and F. Explain why N d) = mg. The maximum magnitude of the friction of the crate on the floor is directly proportional to the magnitude of the normal force. That is, Fmax = AN where is a non-negative real number. It is found that the crate begins to move when the tension exceeds 100 Newtons. Find the value of λ. The rope is now held up by a man so that the angle of elevation of the rope is 0. The man now pulls the rope to the right, keeping the end of the rope at a constant height above the floor. 0 Given that the value of λ does not change, show that in this situation Fmax is reached when: T = 500 5 cos 0+ sin 8

Principles of Physics: A Calculus-Based Text
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Author:Raymond A. Serway, John W. Jewett
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Chapter1: Introduction And Vectors
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Hi, I need help with part d of this question. Thanks.
A 50 kg crate sits on a flat horizortal floor. A rope is attached and pulled horizontally
to the right.
Let T, N and F be the magnitude of the tension force (T), the normal force (N) and the
friction force (F) respectively.
Take acceleration due to gravity to be 10 ms-².
a)
b)
Copy the diagram and show on it the direction of T, N and F.
Explain why N
d)
= mg.
The maximum magnitude of the friction of the crate on the floor is directly
proportional to the magnitude of the normal force. That is, Fmax = AN
where is a non-negative real number.
It is found that the crate begins to move when the tension exceeds 100 Newtons.
Find the value of 2.
The rope is now held up by a man so that the angle of elevation of the rope is 0.
The man now pulls the rope to the right, keeping the end of the rope at a constant
height above the floor.
X
Given that the value of λ does not change, show that in this situation Fmax is
reached when:
T =
500
5 cos 0+ sin 8
Transcribed Image Text:A 50 kg crate sits on a flat horizortal floor. A rope is attached and pulled horizontally to the right. Let T, N and F be the magnitude of the tension force (T), the normal force (N) and the friction force (F) respectively. Take acceleration due to gravity to be 10 ms-². a) b) Copy the diagram and show on it the direction of T, N and F. Explain why N d) = mg. The maximum magnitude of the friction of the crate on the floor is directly proportional to the magnitude of the normal force. That is, Fmax = AN where is a non-negative real number. It is found that the crate begins to move when the tension exceeds 100 Newtons. Find the value of 2. The rope is now held up by a man so that the angle of elevation of the rope is 0. The man now pulls the rope to the right, keeping the end of the rope at a constant height above the floor. X Given that the value of λ does not change, show that in this situation Fmax is reached when: T = 500 5 cos 0+ sin 8
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