A 18.5 kg mass, fastened to the end of a steel wire of unstretched length 1.5 m, is whirled in a vertical circle with an angular velocity of 3 rev/s at the bottom of the circle. The cross-sectional area of the wire is 0.085 cm2. Calculate the elongation of the wire when the mass is at the lowest point of its path
Rotational Equilibrium And Rotational Dynamics
In physics, the state of balance between the forces and the dynamics of motion is called the equilibrium state. The balance between various forces acting on a system in a rotational motion is called rotational equilibrium or rotational dynamics.
Equilibrium of Forces
The tension created on one body during push or pull is known as force.
A 18.5 kg mass, fastened to the end of a steel wire of unstretched length 1.5 m, is whirled in a vertical circle with an
Given:
Original length of the steel wire, L = 1.5 m
Young’s modulus of the steel = 2x1011 N/m2
Mass hung by the wire, m = 18.5 kg
Cross-sectional area of the wire, A = 0.085 cm2
Angular velocity = 3 rev/s
Calculating the tension force in the wire when the mass is at the lowest point of the circle:
At lowest point, the block will have two forces working on it. Tension in upward direction and weight in downward direction. The net force of these forces will provide the necessary centripetal force to the mass to move in a vertical circle.
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