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9-1 (P) 2 2. Since the freezing point of a solution depends on the relative number of particles, what would you calculate to be the freezing point of 0.1 m solutions in water of (a) NaCl, (b) BaCl2? Assume that these salts are 100% ionized in solution. (Compare your answers with the actual respective freezing points: -0.348 °C and -0.470 °C. The difference is due to the decreased activity of the ions. Because of the attractive forces between the positively and negatively charged ions, they do not move completely independently of one another.) g- of 3. How m equ (a) (b) needed to give th

9-1 (P) 2 2. Since the freezing point of a solution depends on the relative number of particles, what would you calculate to be the freezing point of 0.1 m solutions in water of (a) NaCl, (b) BaCl2? Assume that these salts are 100% ionized in solution. (Compare your answers with the actual respective freezing points: -0.348 °C and -0.470 °C. The difference is due to the decreased activity of the ions. Because of the attractive forces between the positively and negatively charged ions, they do not move completely independently of one another.) g- of 3. How m equ (a) (b) needed to give th

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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9-1 (P) 2 2. Since the freezing point of a solution depends on the relative number of particles, what would you calculate to be the freezing point of 0.1 m solutions in water of (a) NaCl, (b) BaCl2? Assume that these salts are 100% ionized in solution. (Compare your answers with the actual respective freezing points: -0.348 °C and -0.470 °C. The difference is due to the decreased activity of the ions. Because of the attractive forces between the positively and negatively charged ions, they do not move completely independently of one another.) g- of 3. How m equ (a) (b) needed to give th
Transcribed Image Text:9-1 (P) 2 2. Since the freezing point of a solution depends on the relative number of particles, what would you calculate to be the freezing point of 0.1 m solutions in water of (a) NaCl, (b) BaCl2? Assume that these salts are 100% ionized in solution. (Compare your answers with the actual respective freezing points: -0.348 °C and -0.470 °C. The difference is due to the decreased activity of the ions. Because of the attractive forces between the positively and negatively charged ions, they do not move completely independently of one another.) g- of 3. How m equ (a) (b) needed to give th
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