4. Is the following solution acidic, basic or neutral? Justify your answer. a. 0.85 M NaHSO4 b. 1.0 x 10-¹0 M NaOH c. 0.75 M NaClO4 5 d. 1.0 M KOC,H, (Ka (HOC,H,)= 1.6 x 10-10) e. 1.0 M CH₂NH₂Cl (Kb (CH₂NH₂) = 4.38 x 10¹4)

Chemistry: An Atoms First Approach
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Author:Steven S. Zumdahl, Susan A. Zumdahl
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Chapter13: Acids And Bases
Section: Chapter Questions
Problem 3RQ
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Solutions for question 4 please
1. Given that the Kw= 1.14 x 10-¹5 at 273 K, what is the pH of
a neutral solution at 273 K?
2. From the data below,
a. Calculate the pH of a 0.75 M maleic acid solution
(H₂C₂H₂O).
b. Find the equilibrium concentration (in M) of C₂H₂O²-
of the 0.75 M maleic acid solution.
(Ka, (H₂C₂H₂O₂)= 1.20x 10³;
Ka₂(H₂C₂H₂O₂)=5.37x10¹7)
3. Given the following Kb value (Kb(NH₂): 1.8 x 10³5)
a. Calculate the pH of a 0.45M NH, solution.
b. Calculate the % dissocation of a 0.45M NH, solution.
c. Calculate the pH of a 0.45M NH₂NO3 solution.
Include the hydrolysis equation that dictates the pH
for this solution.
4. Is the following solution acidic, basic or neutral? Justify
your answer.
2-
a. 0.85 M NaHSO4
b. 1.0 x 10-¹0 M NaOH
c. 0.75 M NaC104
d. 1.0 M KOCH, (Ka (HOC H₂)= 1.6 x 10-¹0)
e. 1.0 M CH₂NH₂Cl (Kb (CH₂NH₂) = 4.38 x 10-4)
Transcribed Image Text:1. Given that the Kw= 1.14 x 10-¹5 at 273 K, what is the pH of a neutral solution at 273 K? 2. From the data below, a. Calculate the pH of a 0.75 M maleic acid solution (H₂C₂H₂O). b. Find the equilibrium concentration (in M) of C₂H₂O²- of the 0.75 M maleic acid solution. (Ka, (H₂C₂H₂O₂)= 1.20x 10³; Ka₂(H₂C₂H₂O₂)=5.37x10¹7) 3. Given the following Kb value (Kb(NH₂): 1.8 x 10³5) a. Calculate the pH of a 0.45M NH, solution. b. Calculate the % dissocation of a 0.45M NH, solution. c. Calculate the pH of a 0.45M NH₂NO3 solution. Include the hydrolysis equation that dictates the pH for this solution. 4. Is the following solution acidic, basic or neutral? Justify your answer. 2- a. 0.85 M NaHSO4 b. 1.0 x 10-¹0 M NaOH c. 0.75 M NaC104 d. 1.0 M KOCH, (Ka (HOC H₂)= 1.6 x 10-¹0) e. 1.0 M CH₂NH₂Cl (Kb (CH₂NH₂) = 4.38 x 10-4)
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